Mass per volume density.
Decagrams per Oil barrel to Drams per Pint Converter — dag/bbl to dr/pt
Convert Decagram per Oil barrel (dag/bbl) to Dram per Pint (dr/pt) using the exact conversion factor (1 decagram per oil barrel = 0.0167971247 dram per pint). See the formula, worked examples, and conversion table.
Decagrams per Oil barrel to Drams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 0.0628981077 / 3.744575854.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Decagrams per Oil barrel to Drams per Pint
Decagram per Oil barrel and Dram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per pint = decagrams per oil barrel × 0.0167971247379
This factor comes from each unit's defined relationship to the category's base unit: 1 decagram per oil barrel equals 0.0628981077043 base units, and 1 dram per pint equals 3.74457585365 base units, so dividing one by the other gives the direct decagram per oil barrel-to-dram per pint factor of 0.0167971247379.
Simple example
1 dag/bbl × 0.01679712474 = 0.0167971247 dr/pt
1 decagram per oil barrel = 0.0167971247 drams per pint.
Real-world example
1,000 dag/bbl × 0.01679712474 = 16.79712474 dr/pt
1,000 decagrams per oil barrel = 16.79712474 drams per pint.
Conversion table
| Decagram per Oil barrel (dag/bbl) | Dram per Pint (dr/pt) |
|---|---|
| 0.1 dag/bbl | 0.0016797125 dr/pt |
| 1 dag/bbl | 0.0167971247 dr/pt |
| 10 dag/bbl | 0.1679712474 dr/pt |
| 100 dag/bbl | 1.679712474 dr/pt |
| 1,000 dag/bbl | 16.79712474 dr/pt |
| 10,000 dag/bbl | 167.9712474 dr/pt |
Reverse conversion: Dram per Pint to Decagram per Oil barrel
0.0167971247 dr/pt × 59.53399856 = 0.9999999977 dag/bbl
0.0167971247 drams per pint = 0.9999999977 decagrams per oil barrel.
decagrams per oil barrel = drams per pint × 59.5339985625
For a page dedicated to this direction, see Dram per Pint to Decagram per Oil barrel.
Understanding the Decagram per Oil barrel (dag/bbl)
Mass per volume density.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per pint are in 1 decagram per oil barrel?
1 decagram per oil barrel equals 0.0167971247 drams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert decagram per oil barrel to dram per pint?
Multiply the decagram per oil barrel value by 0.01679712474. The converter above does this instantly to whatever precision you set.
How do I convert dram per pint back to decagram per oil barrel?
Use the reverse factor: 1 dram per pint equals 59.53399856 decagrams per oil barrel. You can also use the swap control in the converter above to flip the direction instantly.
What is a decagram per oil barrel?
Decagram per Oil barrel (dag/bbl) is a unit of density.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
Is the decagram per oil barrel to dram per pint conversion exact?
Yes. Both decagram per oil barrel and dram per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.01679712474 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.