Mass per volume density.
Decagrams per Cup to Troy ounces per Pint Converter — dag/cup to oz t/pt
Convert Decagram per Cup (dag/cup) to Troy ounce per Pint (oz t/pt) using the exact conversion factor (1 decagram per cup = 0.6430149314 troy ounce per pint). See the formula, worked examples, and conversion table.
Decagrams per Cup to Troy ounces per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 42.26752838 / 65.73335441.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Decagrams per Cup to Troy ounces per Pint
Decagram per Cup and Troy ounce per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per pint = decagrams per cup × 0.643014931373
This factor comes from each unit's defined relationship to the category's base unit: 1 decagram per cup equals 42.2675283773 base units, and 1 troy ounce per pint equals 65.7333544138 base units, so dividing one by the other gives the direct decagram per cup-to-troy ounce per pint factor of 0.643014931373.
Simple example
1 dag/cup × 0.6430149314 = 0.6430149314 oz t/pt
1 decagram per cup = 0.6430149314 troy ounces per pint.
Real-world example
1,000 dag/cup × 0.6430149314 = 643.0149314 oz t/pt
1,000 decagrams per cup = 643.0149314 troy ounces per pint.
Conversion table
| Decagram per Cup (dag/cup) | Troy ounce per Pint (oz t/pt) |
|---|---|
| 0.1 dag/cup | 0.0643014931 oz t/pt |
| 1 dag/cup | 0.6430149314 oz t/pt |
| 10 dag/cup | 6.430149314 oz t/pt |
| 100 dag/cup | 64.30149314 oz t/pt |
| 1,000 dag/cup | 643.0149314 oz t/pt |
| 10,000 dag/cup | 6,430.149314 oz t/pt |
Reverse conversion: Troy ounce per Pint to Decagram per Cup
0.6430149314 oz t/pt × 1.55517384 = 1 dag/cup
0.6430149314 troy ounces per pint = 1 decagrams per cup.
decagrams per cup = troy ounces per pint × 1.55517384
For a page dedicated to this direction, see Troy ounce per Pint to Decagram per Cup.
Understanding the Decagram per Cup (dag/cup)
Mass per volume density.
Understanding the Troy ounce per Pint (oz t/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per pint are in 1 decagram per cup?
1 decagram per cup equals 0.6430149314 troy ounces per pint, using the exact defined conversion factor rather than an estimate.
How do I convert decagram per cup to troy ounce per pint?
Multiply the decagram per cup value by 0.6430149314. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per pint back to decagram per cup?
Use the reverse factor: 1 troy ounce per pint equals 1.55517384 decagrams per cup. You can also use the swap control in the converter above to flip the direction instantly.
What is a decagram per cup?
Decagram per Cup (dag/cup) is a unit of density.
What is a troy ounce per pint?
Troy ounce per Pint (oz t/pt) is a unit of density.
Is the decagram per cup to troy ounce per pint conversion exact?
Yes. Both decagram per cup and troy ounce per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.6430149314 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.