Mass per volume density.
Decagrams per Liter to Drams per Fluid ounce Converter — dag/L to dr/fl oz
Convert Decagram per Liter (dag/L) to Dram per Fluid ounce (dr/fl oz) using the exact conversion factor (1 decagram per liter = 0.166908089 dram per fluid ounce). See the formula, worked examples, and conversion table.
Decagrams per Liter to Drams per Fluid ounce converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 10 / 59.91321366.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Decagrams per Liter to Drams per Fluid ounce
Decagram per Liter and Dram per Fluid ounce both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per fluid ounce = decagrams per liter × 0.16690808904
This factor comes from each unit's defined relationship to the category's base unit: 1 decagram per liter equals 10 base units, and 1 dram per fluid ounce equals 59.9132136584 base units, so dividing one by the other gives the direct decagram per liter-to-dram per fluid ounce factor of 0.16690808904.
Simple example
1 dag/L × 0.166908089 = 0.166908089 dr/fl oz
1 decagram per liter = 0.166908089 drams per fluid ounce.
Real-world example
1,000 dag/L × 0.166908089 = 166.908089 dr/fl oz
1,000 decagrams per liter = 166.908089 drams per fluid ounce.
Conversion table
| Decagram per Liter (dag/L) | Dram per Fluid ounce (dr/fl oz) |
|---|---|
| 0.1 dag/L | 0.0166908089 dr/fl oz |
| 1 dag/L | 0.166908089 dr/fl oz |
| 10 dag/L | 1.66908089 dr/fl oz |
| 100 dag/L | 16.6908089 dr/fl oz |
| 1,000 dag/L | 166.908089 dr/fl oz |
| 10,000 dag/L | 1,669.08089 dr/fl oz |
Reverse conversion: Dram per Fluid ounce to Decagram per Liter
0.166908089 dr/fl oz × 5.991321366 = 0.9999999998 dag/L
0.166908089 drams per fluid ounce = 0.9999999998 decagrams per liter.
decagrams per liter = drams per fluid ounce × 5.99132136584
For a page dedicated to this direction, see Dram per Fluid ounce to Decagram per Liter.
Understanding the Decagram per Liter (dag/L)
Mass per volume density.
Understanding the Dram per Fluid ounce (dr/fl oz)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per fluid ounce are in 1 decagram per liter?
1 decagram per liter equals 0.166908089 drams per fluid ounce, using the exact defined conversion factor rather than an estimate.
How do I convert decagram per liter to dram per fluid ounce?
Multiply the decagram per liter value by 0.166908089. The converter above does this instantly to whatever precision you set.
How do I convert dram per fluid ounce back to decagram per liter?
Use the reverse factor: 1 dram per fluid ounce equals 5.991321366 decagrams per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a decagram per liter?
Decagram per Liter (dag/L) is a unit of density.
What is a dram per fluid ounce?
Dram per Fluid ounce (dr/fl oz) is a unit of density.
Is the decagram per liter to dram per fluid ounce conversion exact?
Yes. Both decagram per liter and dram per fluid ounce are defined by fixed standards rather than physical artifacts, so the factor of 0.166908089 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.