Mass per volume density.
Decagrams per Quart to Troy ounces per Pint Converter — dag/qt to oz t/pt
Convert Decagram per Quart (dag/qt) to Troy ounce per Pint (oz t/pt) using the exact conversion factor (1 decagram per quart = 0.1607537328 troy ounce per pint). See the formula, worked examples, and conversion table.
Decagrams per Quart to Troy ounces per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 10.56688209 / 65.73335441.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Decagrams per Quart to Troy ounces per Pint
Decagram per Quart and Troy ounce per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per pint = decagrams per quart × 0.160753732843
This factor comes from each unit's defined relationship to the category's base unit: 1 decagram per quart equals 10.5668820943 base units, and 1 troy ounce per pint equals 65.7333544138 base units, so dividing one by the other gives the direct decagram per quart-to-troy ounce per pint factor of 0.160753732843.
Simple example
1 dag/qt × 0.1607537328 = 0.1607537328 oz t/pt
1 decagram per quart = 0.1607537328 troy ounces per pint.
Real-world example
1,000 dag/qt × 0.1607537328 = 160.7537328 oz t/pt
1,000 decagrams per quart = 160.7537328 troy ounces per pint.
Conversion table
| Decagram per Quart (dag/qt) | Troy ounce per Pint (oz t/pt) |
|---|---|
| 0.1 dag/qt | 0.0160753733 oz t/pt |
| 1 dag/qt | 0.1607537328 oz t/pt |
| 10 dag/qt | 1.607537328 oz t/pt |
| 100 dag/qt | 16.07537328 oz t/pt |
| 1,000 dag/qt | 160.7537328 oz t/pt |
| 10,000 dag/qt | 1,607.537328 oz t/pt |
Reverse conversion: Troy ounce per Pint to Decagram per Quart
0.1607537328 oz t/pt × 6.22069536 = 0.9999999997 dag/qt
0.1607537328 troy ounces per pint = 0.9999999997 decagrams per quart.
decagrams per quart = troy ounces per pint × 6.22069536
For a page dedicated to this direction, see Troy ounce per Pint to Decagram per Quart.
Understanding the Decagram per Quart (dag/qt)
Mass per volume density.
Understanding the Troy ounce per Pint (oz t/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per pint are in 1 decagram per quart?
1 decagram per quart equals 0.1607537328 troy ounces per pint, using the exact defined conversion factor rather than an estimate.
How do I convert decagram per quart to troy ounce per pint?
Multiply the decagram per quart value by 0.1607537328. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per pint back to decagram per quart?
Use the reverse factor: 1 troy ounce per pint equals 6.22069536 decagrams per quart. You can also use the swap control in the converter above to flip the direction instantly.
What is a decagram per quart?
Decagram per Quart (dag/qt) is a unit of density.
What is a troy ounce per pint?
Troy ounce per Pint (oz t/pt) is a unit of density.
Is the decagram per quart to troy ounce per pint conversion exact?
Yes. Both decagram per quart and troy ounce per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.1607537328 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.