Mass per volume density.
Drams per Cubic yard to Long tons per Cup Converter — dr/yd3 to long ton/cup
Convert Dram per Cubic yard (dr/yd3) to Long ton per Cup (long ton/cup) using the exact conversion factor (1 dram per cubic yard = 5.396305e-10 long ton per cup). See the formula, worked examples, and conversion table.
Drams per Cubic yard to Long tons per Cup converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 0.002317486021 / 4.29457916e+6.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Cubic yard to Long tons per Cup
Dram per Cubic yard and Long ton per Cup both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
long tons per cup = drams per cubic yard × 5.396305e-10
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per cubic yard equals 0.00231748602054 base units, and 1 long ton per cup equals 4294579.15504 base units, so dividing one by the other gives the direct dram per cubic yard-to-long ton per cup factor of 5.396305e-10.
Simple example
1 dr/yd3 × 5.396305e-10 = 5.396305e-10 long ton/cup
1 dram per cubic yard = 5.396305e-10 long tons per cup.
Real-world example
1,000 dr/yd3 × 5.396305e-10 = 5.396305e-7 long ton/cup
1,000 drams per cubic yard = 5.396305e-7 long tons per cup.
Conversion table
| Dram per Cubic yard (dr/yd3) | Long ton per Cup (long ton/cup) |
|---|---|
| 0.1 dr/yd3 | 5.396305e-11 long ton/cup |
| 1 dr/yd3 | 5.396305e-10 long ton/cup |
| 10 dr/yd3 | 5.396305e-9 long ton/cup |
| 100 dr/yd3 | 5.396305e-8 long ton/cup |
| 1,000 dr/yd3 | 5.396305e-7 long ton/cup |
| 10,000 dr/yd3 | 0.0000053963 long ton/cup |
Reverse conversion: Long ton per Cup to Dram per Cubic yard
5.396305e-10 long ton/cup × 1853119767 = 0.9999999466 dr/yd3
5.396305e-10 long tons per cup = 0.9999999466 drams per cubic yard.
drams per cubic yard = long tons per cup × 1853119767.27
For a page dedicated to this direction, see Long ton per Cup to Dram per Cubic yard.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Understanding the Long ton per Cup (long ton/cup)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many long tons per cup are in 1 dram per cubic yard?
1 dram per cubic yard equals 5.396305e-10 long tons per cup, using the exact defined conversion factor rather than an estimate.
How do I convert dram per cubic yard to long ton per cup?
Multiply the dram per cubic yard value by 5.396305e-10. The converter above does this instantly to whatever precision you set.
How do I convert long ton per cup back to dram per cubic yard?
Use the reverse factor: 1 long ton per cup equals 1,853,119,767 drams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
What is a long ton per cup?
Long ton per Cup (long ton/cup) is a unit of density.
Is the dram per cubic yard to long ton per cup conversion exact?
Yes. Both dram per cubic yard and long ton per cup are defined by fixed standards rather than physical artifacts, so the factor of 5.396305e-10 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.