Mass per volume density.
Drams per Cubic yard to Short tons per Liter Converter — dr/yd3 to ton/L
Convert Dram per Cubic yard (dr/yd3) to Short ton per Liter (ton/L) using the exact conversion factor (1 dram per cubic yard = 2.554591e-9 short ton per liter). See the formula, worked examples, and conversion table.
Drams per Cubic yard to Short tons per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 0.002317486021 / 907184.74.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Cubic yard to Short tons per Liter
Dram per Cubic yard and Short ton per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
short tons per liter = drams per cubic yard × 2.554591e-9
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per cubic yard equals 0.00231748602054 base units, and 1 short ton per liter equals 907184.74 base units, so dividing one by the other gives the direct dram per cubic yard-to-short ton per liter factor of 2.554591e-9.
Simple example
1 dr/yd3 × 2.554591e-9 = 2.554591e-9 ton/L
1 dram per cubic yard = 2.554591e-9 short tons per liter.
Real-world example
1,000 dr/yd3 × 2.554591e-9 = 0.0000025546 ton/L
1,000 drams per cubic yard = 0.0000025546 short tons per liter.
Conversion table
| Dram per Cubic yard (dr/yd3) | Short ton per Liter (ton/L) |
|---|---|
| 0.1 dr/yd3 | 2.554591e-10 ton/L |
| 1 dr/yd3 | 2.554591e-9 ton/L |
| 10 dr/yd3 | 2.554591e-8 ton/L |
| 100 dr/yd3 | 2.554591e-7 ton/L |
| 1,000 dr/yd3 | 0.0000025546 ton/L |
| 10,000 dr/yd3 | 0.0000255459 ton/L |
Reverse conversion: Short ton per Liter to Dram per Cubic yard
2.554591e-9 ton/L × 391452087.3 = 0.9999999791 dr/yd3
2.554591e-9 short tons per liter = 0.9999999791 drams per cubic yard.
drams per cubic yard = short tons per liter × 391452087.288
For a page dedicated to this direction, see Short ton per Liter to Dram per Cubic yard.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Understanding the Short ton per Liter (ton/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many short tons per liter are in 1 dram per cubic yard?
1 dram per cubic yard equals 2.554591e-9 short tons per liter, using the exact defined conversion factor rather than an estimate.
How do I convert dram per cubic yard to short ton per liter?
Multiply the dram per cubic yard value by 2.554591e-9. The converter above does this instantly to whatever precision you set.
How do I convert short ton per liter back to dram per cubic yard?
Use the reverse factor: 1 short ton per liter equals 391,452,087.3 drams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
What is a short ton per liter?
Short ton per Liter (ton/L) is a unit of density.
Is the dram per cubic yard to short ton per liter conversion exact?
Yes. Both dram per cubic yard and short ton per liter are defined by fixed standards rather than physical artifacts, so the factor of 2.554591e-9 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.