Mass per volume density.
Drams per Cubic yard to Stones per Gallon Converter — dr/yd3 to st/gal
Convert Dram per Cubic yard (dr/yd3) to Stone per Gallon (st/gal) using the exact conversion factor (1 dram per cubic yard = 0.0000013815 stone per gallon). See the formula, worked examples, and conversion table.
Drams per Cubic yard to Stones per Gallon converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 0.002317486021 / 1677.569982.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Cubic yard to Stones per Gallon
Dram per Cubic yard and Stone per Gallon both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
stones per gallon = drams per cubic yard × 0.00000138145415381
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per cubic yard equals 0.00231748602054 base units, and 1 stone per gallon equals 1677.56998244 base units, so dividing one by the other gives the direct dram per cubic yard-to-stone per gallon factor of 0.00000138145415381.
Simple example
1 dr/yd3 × 0.000001381454154 = 0.0000013815 st/gal
1 dram per cubic yard = 0.0000013815 stones per gallon.
Real-world example
1,000 dr/yd3 × 0.000001381454154 = 0.0013814542 st/gal
1,000 drams per cubic yard = 0.0013814542 stones per gallon.
Conversion table
| Dram per Cubic yard (dr/yd3) | Stone per Gallon (st/gal) |
|---|---|
| 0.1 dr/yd3 | 1.381454e-7 st/gal |
| 1 dr/yd3 | 0.0000013815 st/gal |
| 10 dr/yd3 | 0.0000138145 st/gal |
| 100 dr/yd3 | 0.0001381454 st/gal |
| 1,000 dr/yd3 | 0.0013814542 st/gal |
| 10,000 dr/yd3 | 0.0138145415 st/gal |
Reverse conversion: Stone per Gallon to Dram per Cubic yard
0.0000013815 st/gal × 723874.9091 = 1.000033187 dr/yd3
0.0000013815 stones per gallon = 1.000033187 drams per cubic yard.
drams per cubic yard = stones per gallon × 723874.909091
For a page dedicated to this direction, see Stone per Gallon to Dram per Cubic yard.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Understanding the Stone per Gallon (st/gal)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many stones per gallon are in 1 dram per cubic yard?
1 dram per cubic yard equals 0.0000013815 stones per gallon, using the exact defined conversion factor rather than an estimate.
How do I convert dram per cubic yard to stone per gallon?
Multiply the dram per cubic yard value by 0.000001381454154. The converter above does this instantly to whatever precision you set.
How do I convert stone per gallon back to dram per cubic yard?
Use the reverse factor: 1 stone per gallon equals 723,874.9091 drams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
What is a stone per gallon?
Stone per Gallon (st/gal) is a unit of density.
Is the dram per cubic yard to stone per gallon conversion exact?
Yes. Both dram per cubic yard and stone per gallon are defined by fixed standards rather than physical artifacts, so the factor of 0.000001381454154 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.