Mass per volume density.
Drams per Cubic yard to Troy ounces per Pint Converter — dr/yd3 to oz t/pt
Convert Dram per Cubic yard (dr/yd3) to Troy ounce per Pint (oz t/pt) using the exact conversion factor (1 dram per cubic yard = 0.0000352559 troy ounce per pint). See the formula, worked examples, and conversion table.
Drams per Cubic yard to Troy ounces per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 0.002317486021 / 65.73335441.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Cubic yard to Troy ounces per Pint
Dram per Cubic yard and Troy ounce per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per pint = drams per cubic yard × 0.0000352558612169
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per cubic yard equals 0.00231748602054 base units, and 1 troy ounce per pint equals 65.7333544138 base units, so dividing one by the other gives the direct dram per cubic yard-to-troy ounce per pint factor of 0.0000352558612169.
Simple example
1 dr/yd3 × 0.00003525586122 = 0.0000352559 oz t/pt
1 dram per cubic yard = 0.0000352559 troy ounces per pint.
Real-world example
1,000 dr/yd3 × 0.00003525586122 = 0.0352558612 oz t/pt
1,000 drams per cubic yard = 0.0352558612 troy ounces per pint.
Conversion table
| Dram per Cubic yard (dr/yd3) | Troy ounce per Pint (oz t/pt) |
|---|---|
| 0.1 dr/yd3 | 0.0000035256 oz t/pt |
| 1 dr/yd3 | 0.0000352559 oz t/pt |
| 10 dr/yd3 | 0.0003525586 oz t/pt |
| 100 dr/yd3 | 0.0035255861 oz t/pt |
| 1,000 dr/yd3 | 0.0352558612 oz t/pt |
| 10,000 dr/yd3 | 0.3525586122 oz t/pt |
Reverse conversion: Troy ounce per Pint to Dram per Cubic yard
0.0000352559 oz t/pt × 28364.07807 = 1.0000011 dr/yd3
0.0000352559 troy ounces per pint = 1.0000011 drams per cubic yard.
drams per cubic yard = troy ounces per pint × 28364.0780705
For a page dedicated to this direction, see Troy ounce per Pint to Dram per Cubic yard.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Understanding the Troy ounce per Pint (oz t/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per pint are in 1 dram per cubic yard?
1 dram per cubic yard equals 0.0000352559 troy ounces per pint, using the exact defined conversion factor rather than an estimate.
How do I convert dram per cubic yard to troy ounce per pint?
Multiply the dram per cubic yard value by 0.00003525586122. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per pint back to dram per cubic yard?
Use the reverse factor: 1 troy ounce per pint equals 28,364.07807 drams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
What is a troy ounce per pint?
Troy ounce per Pint (oz t/pt) is a unit of density.
Is the dram per cubic yard to troy ounce per pint conversion exact?
Yes. Both dram per cubic yard and troy ounce per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.00003525586122 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.