Mass per volume density.
Drams per Fluid ounce to Stones per Cubic yard Converter — dr/fl oz to st/yd3
Convert Dram per Fluid ounce (dr/fl oz) to Stone per Cubic yard (st/yd3) using the exact conversion factor (1 dram per fluid ounce = 7.213358071 stone per cubic yard). See the formula, worked examples, and conversion table.
Drams per Fluid ounce to Stones per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 59.91321366 / 8.305869898.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Fluid ounce to Stones per Cubic yard
Dram per Fluid ounce and Stone per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
stones per cubic yard = drams per fluid ounce × 7.2133580705
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per fluid ounce equals 59.9132136584 base units, and 1 stone per cubic yard equals 8.30586989761 base units, so dividing one by the other gives the direct dram per fluid ounce-to-stone per cubic yard factor of 7.2133580705.
Simple example
1 dr/fl oz × 7.213358071 = 7.213358071 st/yd3
1 dram per fluid ounce = 7.213358071 stones per cubic yard.
Real-world example
1,000 dr/fl oz × 7.213358071 = 7,213.358071 st/yd3
1,000 drams per fluid ounce = 7,213.358071 stones per cubic yard.
Conversion table
| Dram per Fluid ounce (dr/fl oz) | Stone per Cubic yard (st/yd3) |
|---|---|
| 0.1 dr/fl oz | 0.7213358071 st/yd3 |
| 1 dr/fl oz | 7.213358071 st/yd3 |
| 10 dr/fl oz | 72.13358071 st/yd3 |
| 100 dr/fl oz | 721.3358071 st/yd3 |
| 1,000 dr/fl oz | 7,213.358071 st/yd3 |
| 10,000 dr/fl oz | 72,133.58071 st/yd3 |
Reverse conversion: Stone per Cubic yard to Dram per Fluid ounce
7.213358071 st/yd3 × 0.1386316872 = 1 dr/fl oz
7.213358071 stones per cubic yard = 1 drams per fluid ounce.
drams per fluid ounce = stones per cubic yard × 0.138631687243
For a page dedicated to this direction, see Stone per Cubic yard to Dram per Fluid ounce.
Understanding the Dram per Fluid ounce (dr/fl oz)
Mass per volume density.
Understanding the Stone per Cubic yard (st/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many stones per cubic yard are in 1 dram per fluid ounce?
1 dram per fluid ounce equals 7.213358071 stones per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert dram per fluid ounce to stone per cubic yard?
Multiply the dram per fluid ounce value by 7.213358071. The converter above does this instantly to whatever precision you set.
How do I convert stone per cubic yard back to dram per fluid ounce?
Use the reverse factor: 1 stone per cubic yard equals 0.1386316872 drams per fluid ounce. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per fluid ounce?
Dram per Fluid ounce (dr/fl oz) is a unit of density.
What is a stone per cubic yard?
Stone per Cubic yard (st/yd3) is a unit of density.
Is the dram per fluid ounce to stone per cubic yard conversion exact?
Yes. Both dram per fluid ounce and stone per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 7.213358071 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.