Mass per volume density.
Drams per Pint to Megagrams per Cubic yard Converter — dr/pt to Mg/yd3
Convert Dram per Pint (dr/pt) to Megagram per Cubic yard (Mg/yd3) using the exact conversion factor (1 dram per pint = 0.0028629337 megagram per cubic yard). See the formula, worked examples, and conversion table.
Drams per Pint to Megagrams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 3.744575854 / 1307.950619.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Pint to Megagrams per Cubic yard
Dram per Pint and Megagram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
megagrams per cubic yard = drams per pint × 0.00286293366
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per pint equals 3.74457585365 base units, and 1 megagram per cubic yard equals 1307.95061931 base units, so dividing one by the other gives the direct dram per pint-to-megagram per cubic yard factor of 0.00286293366.
Simple example
1 dr/pt × 0.00286293366 = 0.0028629337 Mg/yd3
1 dram per pint = 0.0028629337 megagrams per cubic yard.
Real-world example
1,000 dr/pt × 0.00286293366 = 2.86293366 Mg/yd3
1,000 drams per pint = 2.86293366 megagrams per cubic yard.
Conversion table
| Dram per Pint (dr/pt) | Megagram per Cubic yard (Mg/yd3) |
|---|---|
| 0.1 dr/pt | 0.0002862934 Mg/yd3 |
| 1 dr/pt | 0.0028629337 Mg/yd3 |
| 10 dr/pt | 0.0286293366 Mg/yd3 |
| 100 dr/pt | 0.286293366 Mg/yd3 |
| 1,000 dr/pt | 2.86293366 Mg/yd3 |
| 10,000 dr/pt | 28.6293366 Mg/yd3 |
Reverse conversion: Megagram per Cubic yard to Dram per Pint
0.0028629337 Mg/yd3 × 349.2920615 = 1.000000014 dr/pt
0.0028629337 megagrams per cubic yard = 1.000000014 drams per pint.
drams per pint = megagrams per cubic yard × 349.292061486
For a page dedicated to this direction, see Megagram per Cubic yard to Dram per Pint.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Understanding the Megagram per Cubic yard (Mg/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many megagrams per cubic yard are in 1 dram per pint?
1 dram per pint equals 0.0028629337 megagrams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert dram per pint to megagram per cubic yard?
Multiply the dram per pint value by 0.00286293366. The converter above does this instantly to whatever precision you set.
How do I convert megagram per cubic yard back to dram per pint?
Use the reverse factor: 1 megagram per cubic yard equals 349.2920615 drams per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
What is a megagram per cubic yard?
Megagram per Cubic yard (Mg/yd3) is a unit of density.
Is the dram per pint to megagram per cubic yard conversion exact?
Yes. Both dram per pint and megagram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 0.00286293366 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.