Mass per volume density.
Drams per Pint to Metric tons per Cubic foot Converter — dr/pt to t/ft3
Convert Dram per Pint (dr/pt) to Metric ton per Cubic foot (t/ft3) using the exact conversion factor (1 dram per pint = 0.0001060346 metric ton per cubic foot). See the formula, worked examples, and conversion table.
Drams per Pint to Metric tons per Cubic foot converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 3.744575854 / 35314.66672.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Drams per Pint to Metric tons per Cubic foot
Dram per Pint and Metric ton per Cubic foot both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
metric tons per cubic foot = drams per pint × 0.00010603458
This factor comes from each unit's defined relationship to the category's base unit: 1 dram per pint equals 3.74457585365 base units, and 1 metric ton per cubic foot equals 35314.6667215 base units, so dividing one by the other gives the direct dram per pint-to-metric ton per cubic foot factor of 0.00010603458.
Simple example
1 dr/pt × 0.00010603458 = 0.0001060346 t/ft3
1 dram per pint = 0.0001060346 metric tons per cubic foot.
Real-world example
1,000 dr/pt × 0.00010603458 = 0.10603458 t/ft3
1,000 drams per pint = 0.10603458 metric tons per cubic foot.
Conversion table
| Dram per Pint (dr/pt) | Metric ton per Cubic foot (t/ft3) |
|---|---|
| 0.1 dr/pt | 0.0000106035 t/ft3 |
| 1 dr/pt | 0.0001060346 t/ft3 |
| 10 dr/pt | 0.0010603458 t/ft3 |
| 100 dr/pt | 0.010603458 t/ft3 |
| 1,000 dr/pt | 0.10603458 t/ft3 |
| 10,000 dr/pt | 1.0603458 t/ft3 |
Reverse conversion: Metric ton per Cubic foot to Dram per Pint
0.0001060346 t/ft3 × 9430.88566 = 1.000000189 dr/pt
0.0001060346 metric tons per cubic foot = 1.000000189 drams per pint.
drams per pint = metric tons per cubic foot × 9430.88566013
For a page dedicated to this direction, see Metric ton per Cubic foot to Dram per Pint.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Understanding the Metric ton per Cubic foot (t/ft3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many metric tons per cubic foot are in 1 dram per pint?
1 dram per pint equals 0.0001060346 metric tons per cubic foot, using the exact defined conversion factor rather than an estimate.
How do I convert dram per pint to metric ton per cubic foot?
Multiply the dram per pint value by 0.00010603458. The converter above does this instantly to whatever precision you set.
How do I convert metric ton per cubic foot back to dram per pint?
Use the reverse factor: 1 metric ton per cubic foot equals 9,430.88566 drams per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
What is a metric ton per cubic foot?
Metric ton per Cubic foot (t/ft3) is a unit of density.
Is the dram per pint to metric ton per cubic foot conversion exact?
Yes. Both dram per pint and metric ton per cubic foot are defined by fixed standards rather than physical artifacts, so the factor of 0.00010603458 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.