Mass per volume density.
Grams per Cubic yard to Decagrams per Liter Converter — g/yd3 to dag/L
Convert Gram per Cubic yard (g/yd3) to Decagram per Liter (dag/L) using the exact conversion factor (1 gram per cubic yard = 0.0001307951 decagram per liter). See the formula, worked examples, and conversion table.
Grams per Cubic yard to Decagrams per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 0.001307950619 / 10.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Grams per Cubic yard to Decagrams per Liter
Gram per Cubic yard and Decagram per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
decagrams per liter = grams per cubic yard × 0.000130795061931
This factor comes from each unit's defined relationship to the category's base unit: 1 gram per cubic yard equals 0.00130795061931 base units, and 1 decagram per liter equals 10 base units, so dividing one by the other gives the direct gram per cubic yard-to-decagram per liter factor of 0.000130795061931.
Simple example
1 g/yd3 × 0.0001307950619 = 0.0001307951 dag/L
1 gram per cubic yard = 0.0001307951 decagrams per liter.
Real-world example
1,000 g/yd3 × 0.0001307950619 = 0.1307950619 dag/L
1,000 grams per cubic yard = 0.1307950619 decagrams per liter.
Conversion table
| Gram per Cubic yard (g/yd3) | Decagram per Liter (dag/L) |
|---|---|
| 0.1 g/yd3 | 0.0000130795 dag/L |
| 1 g/yd3 | 0.0001307951 dag/L |
| 10 g/yd3 | 0.0013079506 dag/L |
| 100 g/yd3 | 0.0130795062 dag/L |
| 1,000 g/yd3 | 0.1307950619 dag/L |
| 10,000 g/yd3 | 1.307950619 dag/L |
Reverse conversion: Decagram per Liter to Gram per Cubic yard
0.0001307951 dag/L × 7645.54858 = 1.000000291 g/yd3
0.0001307951 decagrams per liter = 1.000000291 grams per cubic yard.
grams per cubic yard = decagrams per liter × 7645.54857984
For a page dedicated to this direction, see Decagram per Liter to Gram per Cubic yard.
Understanding the Gram per Cubic yard (g/yd3)
Mass per volume density.
Understanding the Decagram per Liter (dag/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many decagrams per liter are in 1 gram per cubic yard?
1 gram per cubic yard equals 0.0001307951 decagrams per liter, using the exact defined conversion factor rather than an estimate.
How do I convert gram per cubic yard to decagram per liter?
Multiply the gram per cubic yard value by 0.0001307950619. The converter above does this instantly to whatever precision you set.
How do I convert decagram per liter back to gram per cubic yard?
Use the reverse factor: 1 decagram per liter equals 7,645.54858 grams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a gram per cubic yard?
Gram per Cubic yard (g/yd3) is a unit of density.
What is a decagram per liter?
Decagram per Liter (dag/L) is a unit of density.
Is the gram per cubic yard to decagram per liter conversion exact?
Yes. Both gram per cubic yard and decagram per liter are defined by fixed standards rather than physical artifacts, so the factor of 0.0001307950619 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.