Mass per volume density.
Grams per Cubic yard to Kilograms per Pint Converter — g/yd3 to kg/pt
Convert Gram per Cubic yard (g/yd3) to Kilogram per Pint (kg/pt) using the exact conversion factor (1 gram per cubic yard = 6.188915e-7 kilogram per pint). See the formula, worked examples, and conversion table.
Grams per Cubic yard to Kilograms per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 0.001307950619 / 2113.376419.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Grams per Cubic yard to Kilograms per Pint
Gram per Cubic yard and Kilogram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
kilograms per pint = grams per cubic yard × 6.188915e-7
This factor comes from each unit's defined relationship to the category's base unit: 1 gram per cubic yard equals 0.00130795061931 base units, and 1 kilogram per pint equals 2113.37641887 base units, so dividing one by the other gives the direct gram per cubic yard-to-kilogram per pint factor of 6.188915e-7.
Simple example
1 g/yd3 × 6.188915e-7 = 6.188915e-7 kg/pt
1 gram per cubic yard = 6.188915e-7 kilograms per pint.
Real-world example
1,000 g/yd3 × 6.188915e-7 = 0.0006188915 kg/pt
1,000 grams per cubic yard = 0.0006188915 kilograms per pint.
Conversion table
| Gram per Cubic yard (g/yd3) | Kilogram per Pint (kg/pt) |
|---|---|
| 0.1 g/yd3 | 6.188915e-8 kg/pt |
| 1 g/yd3 | 6.188915e-7 kg/pt |
| 10 g/yd3 | 0.0000061889 kg/pt |
| 100 g/yd3 | 0.0000618891 kg/pt |
| 1,000 g/yd3 | 0.0006188915 kg/pt |
| 10,000 g/yd3 | 0.0061889146 kg/pt |
Reverse conversion: Kilogram per Pint to Gram per Cubic yard
6.188915e-7 kg/pt × 1615792.208 = 1.000000063 g/yd3
6.188915e-7 kilograms per pint = 1.000000063 grams per cubic yard.
grams per cubic yard = kilograms per pint × 1615792.20779
For a page dedicated to this direction, see Kilogram per Pint to Gram per Cubic yard.
Understanding the Gram per Cubic yard (g/yd3)
Mass per volume density.
Understanding the Kilogram per Pint (kg/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many kilograms per pint are in 1 gram per cubic yard?
1 gram per cubic yard equals 6.188915e-7 kilograms per pint, using the exact defined conversion factor rather than an estimate.
How do I convert gram per cubic yard to kilogram per pint?
Multiply the gram per cubic yard value by 6.188915e-7. The converter above does this instantly to whatever precision you set.
How do I convert kilogram per pint back to gram per cubic yard?
Use the reverse factor: 1 kilogram per pint equals 1,615,792.208 grams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a gram per cubic yard?
Gram per Cubic yard (g/yd3) is a unit of density.
What is a kilogram per pint?
Kilogram per Pint (kg/pt) is a unit of density.
Is the gram per cubic yard to kilogram per pint conversion exact?
Yes. Both gram per cubic yard and kilogram per pint are defined by fixed standards rather than physical artifacts, so the factor of 6.188915e-7 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.