Mass per volume density.
Grams per Fluid ounce to Nanograms per Liter Converter — g/fl oz to ng/L
Convert Gram per Fluid ounce (g/fl oz) to Nanogram per Liter (ng/L) using the exact conversion factor (1 gram per fluid ounce = 33,814,022,700 nanogram per liter). See the formula, worked examples, and conversion table.
Grams per Fluid ounce to Nanograms per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 33.8140227 / 1e-9.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Grams per Fluid ounce to Nanograms per Liter
Gram per Fluid ounce and Nanogram per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
nanograms per liter = grams per fluid ounce × 33814022701.8
This factor comes from each unit's defined relationship to the category's base unit: 1 gram per fluid ounce equals 33.8140227018 base units, and 1 nanogram per liter equals 1e-9 base units, so dividing one by the other gives the direct gram per fluid ounce-to-nanogram per liter factor of 33814022701.8.
Simple example
1 g/fl oz × 33814022700 = 33,814,022,700 ng/L
1 gram per fluid ounce = 33,814,022,700 nanograms per liter.
Real-world example
1,000 g/fl oz × 33814022700 = 3.381402e+13 ng/L
1,000 grams per fluid ounce = 3.381402e+13 nanograms per liter.
Conversion table
| Gram per Fluid ounce (g/fl oz) | Nanogram per Liter (ng/L) |
|---|---|
| 0.1 g/fl oz | 3,381,402,270 ng/L |
| 1 g/fl oz | 33,814,022,700 ng/L |
| 10 g/fl oz | 338,140,227,000 ng/L |
| 100 g/fl oz | 3.381402e+12 ng/L |
| 1,000 g/fl oz | 3.381402e+13 ng/L |
| 10,000 g/fl oz | 3.381402e+14 ng/L |
Reverse conversion: Nanogram per Liter to Gram per Fluid ounce
1 ng/L × 2.957353e-11 = 2.957353e-11 g/fl oz
1 nanogram per liter = 2.957353e-11 grams per fluid ounce.
grams per fluid ounce = nanograms per liter × 2.957353e-11
For a page dedicated to this direction, see Nanogram per Liter to Gram per Fluid ounce.
Understanding the Gram per Fluid ounce (g/fl oz)
Mass per volume density.
Understanding the Nanogram per Liter (ng/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many nanograms per liter are in 1 gram per fluid ounce?
1 gram per fluid ounce equals 33,814,022,700 nanograms per liter, using the exact defined conversion factor rather than an estimate.
How do I convert gram per fluid ounce to nanogram per liter?
Multiply the gram per fluid ounce value by 33814022700. The converter above does this instantly to whatever precision you set.
How do I convert nanogram per liter back to gram per fluid ounce?
Use the reverse factor: 1 nanogram per liter equals 2.957353e-11 grams per fluid ounce. You can also use the swap control in the converter above to flip the direction instantly.
What is a gram per fluid ounce?
Gram per Fluid ounce (g/fl oz) is a unit of density.
What is a nanogram per liter?
Nanogram per Liter (ng/L) is a unit of density.
Is the gram per fluid ounce to nanogram per liter conversion exact?
Yes. Both gram per fluid ounce and nanogram per liter are defined by fixed standards rather than physical artifacts, so the factor of 33814022700 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.