Mass per volume density.
Grams per Pint to Troy ounces per Teaspoon Converter — g/pt to oz t/tsp
Convert Gram per Pint (g/pt) to Troy ounce per Teaspoon (oz t/tsp) using the exact conversion factor (1 gram per pint = 0.0003349036 troy ounce per teaspoon). See the formula, worked examples, and conversion table.
Grams per Pint to Troy ounces per Teaspoon converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2.113376419 / 6310.402024.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Grams per Pint to Troy ounces per Teaspoon
Gram per Pint and Troy ounce per Teaspoon both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per teaspoon = grams per pint × 0.00033490361009
This factor comes from each unit's defined relationship to the category's base unit: 1 gram per pint equals 2.11337641887 base units, and 1 troy ounce per teaspoon equals 6310.40202373 base units, so dividing one by the other gives the direct gram per pint-to-troy ounce per teaspoon factor of 0.00033490361009.
Simple example
1 g/pt × 0.0003349036101 = 0.0003349036 oz t/tsp
1 gram per pint = 0.0003349036 troy ounces per teaspoon.
Real-world example
1,000 g/pt × 0.0003349036101 = 0.3349036101 oz t/tsp
1,000 grams per pint = 0.3349036101 troy ounces per teaspoon.
Conversion table
| Gram per Pint (g/pt) | Troy ounce per Teaspoon (oz t/tsp) |
|---|---|
| 0.1 g/pt | 0.0000334904 oz t/tsp |
| 1 g/pt | 0.0003349036 oz t/tsp |
| 10 g/pt | 0.0033490361 oz t/tsp |
| 100 g/pt | 0.033490361 oz t/tsp |
| 1,000 g/pt | 0.3349036101 oz t/tsp |
| 10,000 g/pt | 3.349036101 oz t/tsp |
Reverse conversion: Troy ounce per Teaspoon to Gram per Pint
0.0003349036 oz t/tsp × 2985.933773 = 0.9999999699 g/pt
0.0003349036 troy ounces per teaspoon = 0.9999999699 grams per pint.
grams per pint = troy ounces per teaspoon × 2985.9337728
For a page dedicated to this direction, see Troy ounce per Teaspoon to Gram per Pint.
Understanding the Gram per Pint (g/pt)
Mass per volume density.
Understanding the Troy ounce per Teaspoon (oz t/tsp)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per teaspoon are in 1 gram per pint?
1 gram per pint equals 0.0003349036 troy ounces per teaspoon, using the exact defined conversion factor rather than an estimate.
How do I convert gram per pint to troy ounce per teaspoon?
Multiply the gram per pint value by 0.0003349036101. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per teaspoon back to gram per pint?
Use the reverse factor: 1 troy ounce per teaspoon equals 2,985.933773 grams per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a gram per pint?
Gram per Pint (g/pt) is a unit of density.
What is a troy ounce per teaspoon?
Troy ounce per Teaspoon (oz t/tsp) is a unit of density.
Is the gram per pint to troy ounce per teaspoon conversion exact?
Yes. Both gram per pint and troy ounce per teaspoon are defined by fixed standards rather than physical artifacts, so the factor of 0.0003349036101 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.