Mass per volume density.
US hundredweights per Pint to Kilograms per Quart Converter — cwt/pt to kg/qt
Convert US hundredweight per Pint (cwt/pt) to Kilogram per Quart (kg/qt) using the exact conversion factor (1 us hundredweight per pint = 90.718474 kilogram per quart). See the formula, worked examples, and conversion table.
US hundredweights per Pint to Kilograms per Quart converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 95861.14185 / 1056.688209.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting US hundredweights per Pint to Kilograms per Quart
US hundredweight per Pint and Kilogram per Quart both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
kilograms per quart = us hundredweights per pint × 90.718474
This factor comes from each unit's defined relationship to the category's base unit: 1 us hundredweight per pint equals 95861.1418535 base units, and 1 kilogram per quart equals 1056.68820943 base units, so dividing one by the other gives the direct us hundredweight per pint-to-kilogram per quart factor of 90.718474.
Simple example
1 cwt/pt × 90.718474 = 90.718474 kg/qt
1 us hundredweight per pint = 90.718474 kilograms per quart.
Real-world example
1,000 cwt/pt × 90.718474 = 90,718.474 kg/qt
1,000 us hundredweights per pint = 90,718.474 kilograms per quart.
Conversion table
| US hundredweight per Pint (cwt/pt) | Kilogram per Quart (kg/qt) |
|---|---|
| 0.1 cwt/pt | 9.0718474 kg/qt |
| 1 cwt/pt | 90.718474 kg/qt |
| 10 cwt/pt | 907.18474 kg/qt |
| 100 cwt/pt | 9,071.8474 kg/qt |
| 1,000 cwt/pt | 90,718.474 kg/qt |
| 10,000 cwt/pt | 907,184.74 kg/qt |
Reverse conversion: Kilogram per Quart to US hundredweight per Pint
90.718474 kg/qt × 0.01102311311 = 1 cwt/pt
90.718474 kilograms per quart = 1 us hundredweight per pint.
us hundredweights per pint = kilograms per quart × 0.0110231131092
For a page dedicated to this direction, see Kilogram per Quart to US hundredweight per Pint.
Understanding the US hundredweight per Pint (cwt/pt)
Mass per volume density.
Understanding the Kilogram per Quart (kg/qt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many kilograms per quart are in 1 us hundredweight per pint?
1 us hundredweight per pint equals 90.718474 kilograms per quart, using the exact defined conversion factor rather than an estimate.
How do I convert us hundredweight per pint to kilogram per quart?
Multiply the us hundredweight per pint value by 90.718474. The converter above does this instantly to whatever precision you set.
How do I convert kilogram per quart back to us hundredweight per pint?
Use the reverse factor: 1 kilogram per quart equals 0.0110231131 us hundredweights per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a us hundredweight per pint?
US hundredweight per Pint (cwt/pt) is a unit of density.
What is a kilogram per quart?
Kilogram per Quart (kg/qt) is a unit of density.
Is the us hundredweight per pint to kilogram per quart conversion exact?
Yes. Both us hundredweight per pint and kilogram per quart are defined by fixed standards rather than physical artifacts, so the factor of 90.718474 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.