Mass per volume density.
Kilograms per Pint to Drams per Fluid ounce Converter — kg/pt to dr/fl oz
Convert Kilogram per Pint (kg/pt) to Dram per Fluid ounce (dr/fl oz) using the exact conversion factor (1 kilogram per pint = 35.27396195 dram per fluid ounce). See the formula, worked examples, and conversion table.
Kilograms per Pint to Drams per Fluid ounce converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2113.376419 / 59.91321366.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Kilograms per Pint to Drams per Fluid ounce
Kilogram per Pint and Dram per Fluid ounce both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per fluid ounce = kilograms per pint × 35.2739619496
This factor comes from each unit's defined relationship to the category's base unit: 1 kilogram per pint equals 2113.37641887 base units, and 1 dram per fluid ounce equals 59.9132136584 base units, so dividing one by the other gives the direct kilogram per pint-to-dram per fluid ounce factor of 35.2739619496.
Simple example
1 kg/pt × 35.27396195 = 35.27396195 dr/fl oz
1 kilogram per pint = 35.27396195 drams per fluid ounce.
Real-world example
1,000 kg/pt × 35.27396195 = 35,273.96195 dr/fl oz
1,000 kilograms per pint = 35,273.96195 drams per fluid ounce.
Conversion table
| Kilogram per Pint (kg/pt) | Dram per Fluid ounce (dr/fl oz) |
|---|---|
| 0.1 kg/pt | 3.527396195 dr/fl oz |
| 1 kg/pt | 35.27396195 dr/fl oz |
| 10 kg/pt | 352.7396195 dr/fl oz |
| 100 kg/pt | 3,527.396195 dr/fl oz |
| 1,000 kg/pt | 35,273.96195 dr/fl oz |
| 10,000 kg/pt | 352,739.6195 dr/fl oz |
Reverse conversion: Dram per Fluid ounce to Kilogram per Pint
35.27396195 dr/fl oz × 0.02834952313 = 1 kg/pt
35.27396195 drams per fluid ounce = 1 kilograms per pint.
kilograms per pint = drams per fluid ounce × 0.028349523125
For a page dedicated to this direction, see Dram per Fluid ounce to Kilogram per Pint.
Understanding the Kilogram per Pint (kg/pt)
Mass per volume density.
Understanding the Dram per Fluid ounce (dr/fl oz)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per fluid ounce are in 1 kilogram per pint?
1 kilogram per pint equals 35.27396195 drams per fluid ounce, using the exact defined conversion factor rather than an estimate.
How do I convert kilogram per pint to dram per fluid ounce?
Multiply the kilogram per pint value by 35.27396195. The converter above does this instantly to whatever precision you set.
How do I convert dram per fluid ounce back to kilogram per pint?
Use the reverse factor: 1 dram per fluid ounce equals 0.0283495231 kilograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a kilogram per pint?
Kilogram per Pint (kg/pt) is a unit of density.
What is a dram per fluid ounce?
Dram per Fluid ounce (dr/fl oz) is a unit of density.
Is the kilogram per pint to dram per fluid ounce conversion exact?
Yes. Both kilogram per pint and dram per fluid ounce are defined by fixed standards rather than physical artifacts, so the factor of 35.27396195 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.