Mass per volume density.
Kilograms per Pint to Troy ounces per Cup Converter — kg/pt to oz t/cup
Convert Kilogram per Pint (kg/pt) to Troy ounce per Cup (oz t/cup) using the exact conversion factor (1 kilogram per pint = 16.07537328 troy ounce per cup). See the formula, worked examples, and conversion table.
Kilograms per Pint to Troy ounces per Cup converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2113.376419 / 131.4667088.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Kilograms per Pint to Troy ounces per Cup
Kilogram per Pint and Troy ounce per Cup both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per cup = kilograms per pint × 16.0753732843
This factor comes from each unit's defined relationship to the category's base unit: 1 kilogram per pint equals 2113.37641887 base units, and 1 troy ounce per cup equals 131.466708828 base units, so dividing one by the other gives the direct kilogram per pint-to-troy ounce per cup factor of 16.0753732843.
Simple example
1 kg/pt × 16.07537328 = 16.07537328 oz t/cup
1 kilogram per pint = 16.07537328 troy ounces per cup.
Real-world example
1,000 kg/pt × 16.07537328 = 16,075.37328 oz t/cup
1,000 kilograms per pint = 16,075.37328 troy ounces per cup.
Conversion table
| Kilogram per Pint (kg/pt) | Troy ounce per Cup (oz t/cup) |
|---|---|
| 0.1 kg/pt | 1.607537328 oz t/cup |
| 1 kg/pt | 16.07537328 oz t/cup |
| 10 kg/pt | 160.7537328 oz t/cup |
| 100 kg/pt | 1,607.537328 oz t/cup |
| 1,000 kg/pt | 16,075.37328 oz t/cup |
| 10,000 kg/pt | 160,753.7328 oz t/cup |
Reverse conversion: Troy ounce per Cup to Kilogram per Pint
16.07537328 oz t/cup × 0.0622069536 = 0.9999999997 kg/pt
16.07537328 troy ounces per cup = 0.9999999997 kilograms per pint.
kilograms per pint = troy ounces per cup × 0.0622069536
For a page dedicated to this direction, see Troy ounce per Cup to Kilogram per Pint.
Understanding the Kilogram per Pint (kg/pt)
Mass per volume density.
Understanding the Troy ounce per Cup (oz t/cup)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per cup are in 1 kilogram per pint?
1 kilogram per pint equals 16.07537328 troy ounces per cup, using the exact defined conversion factor rather than an estimate.
How do I convert kilogram per pint to troy ounce per cup?
Multiply the kilogram per pint value by 16.07537328. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per cup back to kilogram per pint?
Use the reverse factor: 1 troy ounce per cup equals 0.0622069536 kilograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a kilogram per pint?
Kilogram per Pint (kg/pt) is a unit of density.
What is a troy ounce per cup?
Troy ounce per Cup (oz t/cup) is a unit of density.
Is the kilogram per pint to troy ounce per cup conversion exact?
Yes. Both kilogram per pint and troy ounce per cup are defined by fixed standards rather than physical artifacts, so the factor of 16.07537328 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.