Mass per volume density.
Kilograms per Pint to Troy ounces per Liter Converter — kg/pt to oz t/L
Convert Kilogram per Pint (kg/pt) to Troy ounce per Liter (oz t/L) using the exact conversion factor (1 kilogram per pint = 67.94662965 troy ounce per liter). See the formula, worked examples, and conversion table.
Kilograms per Pint to Troy ounces per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2113.376419 / 31.1034768.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Kilograms per Pint to Troy ounces per Liter
Kilogram per Pint and Troy ounce per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per liter = kilograms per pint × 67.946629647
This factor comes from each unit's defined relationship to the category's base unit: 1 kilogram per pint equals 2113.37641887 base units, and 1 troy ounce per liter equals 31.1034768 base units, so dividing one by the other gives the direct kilogram per pint-to-troy ounce per liter factor of 67.946629647.
Simple example
1 kg/pt × 67.94662965 = 67.94662965 oz t/L
1 kilogram per pint = 67.94662965 troy ounces per liter.
Real-world example
1,000 kg/pt × 67.94662965 = 67,946.62965 oz t/L
1,000 kilograms per pint = 67,946.62965 troy ounces per liter.
Conversion table
| Kilogram per Pint (kg/pt) | Troy ounce per Liter (oz t/L) |
|---|---|
| 0.1 kg/pt | 6.794662965 oz t/L |
| 1 kg/pt | 67.94662965 oz t/L |
| 10 kg/pt | 679.4662965 oz t/L |
| 100 kg/pt | 6,794.662965 oz t/L |
| 1,000 kg/pt | 67,946.62965 oz t/L |
| 10,000 kg/pt | 679,466.2965 oz t/L |
Reverse conversion: Troy ounce per Liter to Kilogram per Pint
67.94662965 oz t/L × 0.01471743345 = 1 kg/pt
67.94662965 troy ounces per liter = 1 kilograms per pint.
kilograms per pint = troy ounces per liter × 0.0147174334503
For a page dedicated to this direction, see Troy ounce per Liter to Kilogram per Pint.
Understanding the Kilogram per Pint (kg/pt)
Mass per volume density.
Understanding the Troy ounce per Liter (oz t/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per liter are in 1 kilogram per pint?
1 kilogram per pint equals 67.94662965 troy ounces per liter, using the exact defined conversion factor rather than an estimate.
How do I convert kilogram per pint to troy ounce per liter?
Multiply the kilogram per pint value by 67.94662965. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per liter back to kilogram per pint?
Use the reverse factor: 1 troy ounce per liter equals 0.0147174335 kilograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a kilogram per pint?
Kilogram per Pint (kg/pt) is a unit of density.
What is a troy ounce per liter?
Troy ounce per Liter (oz t/L) is a unit of density.
Is the kilogram per pint to troy ounce per liter conversion exact?
Yes. Both kilogram per pint and troy ounce per liter are defined by fixed standards rather than physical artifacts, so the factor of 67.94662965 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.