Mass per volume density.
Kilograms per Quart to Drams per Cubic foot Converter — kg/qt to dr/ft3
Convert Kilogram per Quart (kg/qt) to Dram per Cubic foot (dr/ft3) using the exact conversion factor (1 kilogram per quart = 16,887.52381 dram per cubic foot). See the formula, worked examples, and conversion table.
Kilograms per Quart to Drams per Cubic foot converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1056.688209 / 0.06257212255.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Kilograms per Quart to Drams per Cubic foot
Kilogram per Quart and Dram per Cubic foot both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic foot = kilograms per quart × 16887.5238092
This factor comes from each unit's defined relationship to the category's base unit: 1 kilogram per quart equals 1056.68820943 base units, and 1 dram per cubic foot equals 0.0625721225545 base units, so dividing one by the other gives the direct kilogram per quart-to-dram per cubic foot factor of 16887.5238092.
Simple example
1 kg/qt × 16887.52381 = 16,887.52381 dr/ft3
1 kilogram per quart = 16,887.52381 drams per cubic foot.
Real-world example
1,000 kg/qt × 16887.52381 = 16,887,523.81 dr/ft3
1,000 kilograms per quart = 16,887,523.81 drams per cubic foot.
Conversion table
| Kilogram per Quart (kg/qt) | Dram per Cubic foot (dr/ft3) |
|---|---|
| 0.1 kg/qt | 1,688.752381 dr/ft3 |
| 1 kg/qt | 16,887.52381 dr/ft3 |
| 10 kg/qt | 168,875.2381 dr/ft3 |
| 100 kg/qt | 1,688,752.381 dr/ft3 |
| 1,000 kg/qt | 16,887,523.81 dr/ft3 |
| 10,000 kg/qt | 168,875,238.1 dr/ft3 |
Reverse conversion: Dram per Cubic foot to Kilogram per Quart
1 dr/ft3 × 0.00005921531252 = 0.0000592153 kg/qt
1 dram per cubic foot = 0.0000592153 kilograms per quart.
kilograms per quart = drams per cubic foot × 0.000059215312517
For a page dedicated to this direction, see Dram per Cubic foot to Kilogram per Quart.
Understanding the Kilogram per Quart (kg/qt)
Mass per volume density.
Understanding the Dram per Cubic foot (dr/ft3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic foot are in 1 kilogram per quart?
1 kilogram per quart equals 16,887.52381 drams per cubic foot, using the exact defined conversion factor rather than an estimate.
How do I convert kilogram per quart to dram per cubic foot?
Multiply the kilogram per quart value by 16887.52381. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic foot back to kilogram per quart?
Use the reverse factor: 1 dram per cubic foot equals 0.0000592153 kilograms per quart. You can also use the swap control in the converter above to flip the direction instantly.
What is a kilogram per quart?
Kilogram per Quart (kg/qt) is a unit of density.
What is a dram per cubic foot?
Dram per Cubic foot (dr/ft3) is a unit of density.
Is the kilogram per quart to dram per cubic foot conversion exact?
Yes. Both kilogram per quart and dram per cubic foot are defined by fixed standards rather than physical artifacts, so the factor of 16887.52381 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.