Mass per volume density.
Long tons per Cubic yard to Grams per Pint Converter — long ton/yd3 to g/pt
Convert Long ton per Cubic yard (long ton/yd3) to Gram per Pint (g/pt) using the exact conversion factor (1 long ton per cubic yard = 628.8227557 gram per pint). See the formula, worked examples, and conversion table.
Long tons per Cubic yard to Grams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 1328.939184 / 2.113376419.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Long tons per Cubic yard to Grams per Pint
Long ton per Cubic yard and Gram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
grams per pint = long tons per cubic yard × 628.822755736
This factor comes from each unit's defined relationship to the category's base unit: 1 long ton per cubic yard equals 1328.93918362 base units, and 1 gram per pint equals 2.11337641887 base units, so dividing one by the other gives the direct long ton per cubic yard-to-gram per pint factor of 628.822755736.
Simple example
1 long ton/yd3 × 628.8227557 = 628.8227557 g/pt
1 long ton per cubic yard = 628.8227557 grams per pint.
Real-world example
1,000 long ton/yd3 × 628.8227557 = 628,822.7557 g/pt
1,000 long tons per cubic yard = 628,822.7557 grams per pint.
Conversion table
| Long ton per Cubic yard (long ton/yd3) | Gram per Pint (g/pt) |
|---|---|
| 0.1 long ton/yd3 | 62.88227557 g/pt |
| 1 long ton/yd3 | 628.8227557 g/pt |
| 10 long ton/yd3 | 6,288.227557 g/pt |
| 100 long ton/yd3 | 62,882.27557 g/pt |
| 1,000 long ton/yd3 | 628,822.7557 g/pt |
| 10,000 long ton/yd3 | 6,288,227.557 g/pt |
Reverse conversion: Gram per Pint to Long ton per Cubic yard
628.8227557 g/pt × 0.001590273238 = 0.9999999999 long ton/yd3
628.8227557 grams per pint = 0.9999999999 long tons per cubic yard.
long tons per cubic yard = grams per pint × 0.00159027323817
For a page dedicated to this direction, see Gram per Pint to Long ton per Cubic yard.
Understanding the Long ton per Cubic yard (long ton/yd3)
Mass per volume density.
Understanding the Gram per Pint (g/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many grams per pint are in 1 long ton per cubic yard?
1 long ton per cubic yard equals 628.8227557 grams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert long ton per cubic yard to gram per pint?
Multiply the long ton per cubic yard value by 628.8227557. The converter above does this instantly to whatever precision you set.
How do I convert gram per pint back to long ton per cubic yard?
Use the reverse factor: 1 gram per pint equals 0.0015902732 long tons per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a long ton per cubic yard?
Long ton per Cubic yard (long ton/yd3) is a unit of density.
What is a gram per pint?
Gram per Pint (g/pt) is a unit of density.
Is the long ton per cubic yard to gram per pint conversion exact?
Yes. Both long ton per cubic yard and gram per pint are defined by fixed standards rather than physical artifacts, so the factor of 628.8227557 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.