Mass per volume density.
Megagrams per Cubic yard to Pounds per Pint Converter — Mg/yd3 to lb/pt
Convert Megagram per Cubic yard (Mg/yd3) to Pound per Pint (lb/pt) using the exact conversion factor (1 megagram per cubic yard = 1.364422115 pound per pint). See the formula, worked examples, and conversion table.
Megagrams per Cubic yard to Pounds per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1307.950619 / 958.6114185.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Megagrams per Cubic yard to Pounds per Pint
Megagram per Cubic yard and Pound per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
pounds per pint = megagrams per cubic yard × 1.36442211518
This factor comes from each unit's defined relationship to the category's base unit: 1 megagram per cubic yard equals 1307.95061931 base units, and 1 pound per pint equals 958.611418535 base units, so dividing one by the other gives the direct megagram per cubic yard-to-pound per pint factor of 1.36442211518.
Simple example
1 Mg/yd3 × 1.364422115 = 1.364422115 lb/pt
1 megagram per cubic yard = 1.364422115 pounds per pint.
Real-world example
1,000 Mg/yd3 × 1.364422115 = 1,364.422115 lb/pt
1,000 megagrams per cubic yard = 1,364.422115 pounds per pint.
Conversion table
| Megagram per Cubic yard (Mg/yd3) | Pound per Pint (lb/pt) |
|---|---|
| 0.1 Mg/yd3 | 0.1364422115 lb/pt |
| 1 Mg/yd3 | 1.364422115 lb/pt |
| 10 Mg/yd3 | 13.64422115 lb/pt |
| 100 Mg/yd3 | 136.4422115 lb/pt |
| 1,000 Mg/yd3 | 1,364.422115 lb/pt |
| 10,000 Mg/yd3 | 13,644.22115 lb/pt |
Reverse conversion: Pound per Pint to Megagram per Cubic yard
1.364422115 lb/pt × 0.732911017 = 0.9999999999 Mg/yd3
1.364422115 pounds per pint = 0.9999999999 megagrams per cubic yard.
megagrams per cubic yard = pounds per pint × 0.73291101696
For a page dedicated to this direction, see Pound per Pint to Megagram per Cubic yard.
Understanding the Megagram per Cubic yard (Mg/yd3)
Mass per volume density.
Understanding the Pound per Pint (lb/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many pounds per pint are in 1 megagram per cubic yard?
1 megagram per cubic yard equals 1.364422115 pounds per pint, using the exact defined conversion factor rather than an estimate.
How do I convert megagram per cubic yard to pound per pint?
Multiply the megagram per cubic yard value by 1.364422115. The converter above does this instantly to whatever precision you set.
How do I convert pound per pint back to megagram per cubic yard?
Use the reverse factor: 1 pound per pint equals 0.732911017 megagrams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a megagram per cubic yard?
Megagram per Cubic yard (Mg/yd3) is a unit of density.
What is a pound per pint?
Pound per Pint (lb/pt) is a unit of density.
Is the megagram per cubic yard to pound per pint conversion exact?
Yes. Both megagram per cubic yard and pound per pint are defined by fixed standards rather than physical artifacts, so the factor of 1.364422115 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.