Mass per volume density.
Micrograms per Cubic Meter to Drams per Pint Converter — ug/m3 to dr/pt
Convert Microgram per Cubic Meter (ug/m3) to Dram per Pint (dr/pt) using the exact conversion factor (1 microgram per cubic meter = 2.670529e-10 dram per pint). See the formula, worked examples, and conversion table.
Micrograms per Cubic Meter to Drams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1e-9 / 3.744575854.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Micrograms per Cubic Meter to Drams per Pint
Microgram per Cubic Meter and Dram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per pint = micrograms per cubic meter × 2.670529e-10
This factor comes from each unit's defined relationship to the category's base unit: 1 microgram per cubic meter equals 1e-9 base units, and 1 dram per pint equals 3.74457585365 base units, so dividing one by the other gives the direct microgram per cubic meter-to-dram per pint factor of 2.670529e-10.
Simple example
1 ug/m3 × 2.670529e-10 = 2.670529e-10 dr/pt
1 microgram per cubic meter = 2.670529e-10 drams per pint.
Real-world example
1,000 ug/m3 × 2.670529e-10 = 2.670529e-7 dr/pt
1,000 micrograms per cubic meter = 2.670529e-7 drams per pint.
Conversion table
| Microgram per Cubic Meter (ug/m3) | Dram per Pint (dr/pt) |
|---|---|
| 0.1 ug/m3 | 2.670529e-11 dr/pt |
| 1 ug/m3 | 2.670529e-10 dr/pt |
| 10 ug/m3 | 2.670529e-9 dr/pt |
| 100 ug/m3 | 2.670529e-8 dr/pt |
| 1,000 ug/m3 | 2.670529e-7 dr/pt |
| 10,000 ug/m3 | 0.0000026705 dr/pt |
Reverse conversion: Dram per Pint to Microgram per Cubic Meter
2.670529e-10 dr/pt × 3744575854 = 0.999999841 ug/m3
2.670529e-10 drams per pint = 0.999999841 micrograms per cubic meter.
micrograms per cubic meter = drams per pint × 3744575853.65
For a page dedicated to this direction, see Dram per Pint to Microgram per Cubic Meter.
Understanding the Microgram per Cubic Meter (ug/m3)
Mass per volume density.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per pint are in 1 microgram per cubic meter?
1 microgram per cubic meter equals 2.670529e-10 drams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert microgram per cubic meter to dram per pint?
Multiply the microgram per cubic meter value by 2.670529e-10. The converter above does this instantly to whatever precision you set.
How do I convert dram per pint back to microgram per cubic meter?
Use the reverse factor: 1 dram per pint equals 3,744,575,854 micrograms per cubic meter. You can also use the swap control in the converter above to flip the direction instantly.
What is a microgram per cubic meter?
Microgram per Cubic Meter (ug/m3) is a unit of density.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
Is the microgram per cubic meter to dram per pint conversion exact?
Yes. Both microgram per cubic meter and dram per pint are defined by fixed standards rather than physical artifacts, so the factor of 2.670529e-10 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.