Mass per volume density.
Milligrams per Cubic yard to Drams per Pint Converter — mg/yd3 to dr/pt
Convert Milligram per Cubic yard (mg/yd3) to Dram per Pint (dr/pt) using the exact conversion factor (1 milligram per cubic yard = 3.492921e-7 dram per pint). See the formula, worked examples, and conversion table.
Milligrams per Cubic yard to Drams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1.30795062e-6 / 3.744575854.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Milligrams per Cubic yard to Drams per Pint
Milligram per Cubic yard and Dram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per pint = milligrams per cubic yard × 3.492921e-7
This factor comes from each unit's defined relationship to the category's base unit: 1 milligram per cubic yard equals 0.00000130795061931 base units, and 1 dram per pint equals 3.74457585365 base units, so dividing one by the other gives the direct milligram per cubic yard-to-dram per pint factor of 3.492921e-7.
Simple example
1 mg/yd3 × 3.492921e-7 = 3.492921e-7 dr/pt
1 milligram per cubic yard = 3.492921e-7 drams per pint.
Real-world example
1,000 mg/yd3 × 3.492921e-7 = 0.0003492921 dr/pt
1,000 milligrams per cubic yard = 0.0003492921 drams per pint.
Conversion table
| Milligram per Cubic yard (mg/yd3) | Dram per Pint (dr/pt) |
|---|---|
| 0.1 mg/yd3 | 3.492921e-8 dr/pt |
| 1 mg/yd3 | 3.492921e-7 dr/pt |
| 10 mg/yd3 | 0.0000034929 dr/pt |
| 100 mg/yd3 | 0.0000349292 dr/pt |
| 1,000 mg/yd3 | 0.0003492921 dr/pt |
| 10,000 mg/yd3 | 0.0034929206 dr/pt |
Reverse conversion: Dram per Pint to Milligram per Cubic yard
3.492921e-7 dr/pt × 2862933.66 = 1.00000011 mg/yd3
3.492921e-7 drams per pint = 1.00000011 milligrams per cubic yard.
milligrams per cubic yard = drams per pint × 2862933.66
For a page dedicated to this direction, see Dram per Pint to Milligram per Cubic yard.
Understanding the Milligram per Cubic yard (mg/yd3)
Mass per volume density.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per pint are in 1 milligram per cubic yard?
1 milligram per cubic yard equals 3.492921e-7 drams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert milligram per cubic yard to dram per pint?
Multiply the milligram per cubic yard value by 3.492921e-7. The converter above does this instantly to whatever precision you set.
How do I convert dram per pint back to milligram per cubic yard?
Use the reverse factor: 1 dram per pint equals 2,862,933.66 milligrams per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a milligram per cubic yard?
Milligram per Cubic yard (mg/yd3) is a unit of density.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
Is the milligram per cubic yard to dram per pint conversion exact?
Yes. Both milligram per cubic yard and dram per pint are defined by fixed standards rather than physical artifacts, so the factor of 3.492921e-7 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.