Mass per volume density.
Nanograms per Liter to Drams per Cubic yard Converter — ng/L to dr/yd3
Convert Nanogram per Liter (ng/L) to Dram per Cubic yard (dr/yd3) using the exact conversion factor (1 nanogram per liter = 4.315021e-7 dram per cubic yard). See the formula, worked examples, and conversion table.
Nanograms per Liter to Drams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1e-9 / 0.002317486021.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Nanograms per Liter to Drams per Cubic yard
Nanogram per Liter and Dram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic yard = nanograms per liter × 4.315021e-7
This factor comes from each unit's defined relationship to the category's base unit: 1 nanogram per liter equals 1e-9 base units, and 1 dram per cubic yard equals 0.00231748602054 base units, so dividing one by the other gives the direct nanogram per liter-to-dram per cubic yard factor of 4.315021e-7.
Simple example
1 ng/L × 4.315021e-7 = 4.315021e-7 dr/yd3
1 nanogram per liter = 4.315021e-7 drams per cubic yard.
Real-world example
1,000 ng/L × 4.315021e-7 = 0.0004315021 dr/yd3
1,000 nanograms per liter = 0.0004315021 drams per cubic yard.
Conversion table
| Nanogram per Liter (ng/L) | Dram per Cubic yard (dr/yd3) |
|---|---|
| 0.1 ng/L | 4.315021e-8 dr/yd3 |
| 1 ng/L | 4.315021e-7 dr/yd3 |
| 10 ng/L | 0.000004315 dr/yd3 |
| 100 ng/L | 0.0000431502 dr/yd3 |
| 1,000 ng/L | 0.0004315021 dr/yd3 |
| 10,000 ng/L | 0.0043150206 dr/yd3 |
Reverse conversion: Dram per Cubic yard to Nanogram per Liter
4.315021e-7 dr/yd3 × 2317486.021 = 1.000000085 ng/L
4.315021e-7 drams per cubic yard = 1.000000085 nanograms per liter.
nanograms per liter = drams per cubic yard × 2317486.02054
For a page dedicated to this direction, see Dram per Cubic yard to Nanogram per Liter.
Understanding the Nanogram per Liter (ng/L)
Mass per volume density.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic yard are in 1 nanogram per liter?
1 nanogram per liter equals 4.315021e-7 drams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert nanogram per liter to dram per cubic yard?
Multiply the nanogram per liter value by 4.315021e-7. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic yard back to nanogram per liter?
Use the reverse factor: 1 dram per cubic yard equals 2,317,486.021 nanograms per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a nanogram per liter?
Nanogram per Liter (ng/L) is a unit of density.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
Is the nanogram per liter to dram per cubic yard conversion exact?
Yes. Both nanogram per liter and dram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 4.315021e-7 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.