Mass per volume density.
Nanograms per Pint to Drams per Cubic foot Converter — ng/pt to dr/ft3
Convert Nanogram per Pint (ng/pt) to Dram per Cubic foot (dr/ft3) using the exact conversion factor (1 nanogram per pint = 3.377505e-8 dram per cubic foot). See the formula, worked examples, and conversion table.
Nanograms per Pint to Drams per Cubic foot converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2.11337642e-9 / 0.06257212255.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Nanograms per Pint to Drams per Cubic foot
Nanogram per Pint and Dram per Cubic foot both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic foot = nanograms per pint × 3.377505e-8
This factor comes from each unit's defined relationship to the category's base unit: 1 nanogram per pint equals 2.113376e-9 base units, and 1 dram per cubic foot equals 0.0625721225545 base units, so dividing one by the other gives the direct nanogram per pint-to-dram per cubic foot factor of 3.377505e-8.
Simple example
1 ng/pt × 3.377505e-8 = 3.377505e-8 dr/ft3
1 nanogram per pint = 3.377505e-8 drams per cubic foot.
Real-world example
1,000 ng/pt × 3.377505e-8 = 0.000033775 dr/ft3
1,000 nanograms per pint = 0.000033775 drams per cubic foot.
Conversion table
| Nanogram per Pint (ng/pt) | Dram per Cubic foot (dr/ft3) |
|---|---|
| 0.1 ng/pt | 3.377505e-9 dr/ft3 |
| 1 ng/pt | 3.377505e-8 dr/ft3 |
| 10 ng/pt | 3.377505e-7 dr/ft3 |
| 100 ng/pt | 0.0000033775 dr/ft3 |
| 1,000 ng/pt | 0.000033775 dr/ft3 |
| 10,000 ng/pt | 0.0003377505 dr/ft3 |
Reverse conversion: Dram per Cubic foot to Nanogram per Pint
3.377505e-8 dr/ft3 × 29607656.26 = 1.000000071 ng/pt
3.377505e-8 drams per cubic foot = 1.000000071 nanograms per pint.
nanograms per pint = drams per cubic foot × 29607656.2585
For a page dedicated to this direction, see Dram per Cubic foot to Nanogram per Pint.
Understanding the Nanogram per Pint (ng/pt)
Mass per volume density.
Understanding the Dram per Cubic foot (dr/ft3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic foot are in 1 nanogram per pint?
1 nanogram per pint equals 3.377505e-8 drams per cubic foot, using the exact defined conversion factor rather than an estimate.
How do I convert nanogram per pint to dram per cubic foot?
Multiply the nanogram per pint value by 3.377505e-8. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic foot back to nanogram per pint?
Use the reverse factor: 1 dram per cubic foot equals 29,607,656.26 nanograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a nanogram per pint?
Nanogram per Pint (ng/pt) is a unit of density.
What is a dram per cubic foot?
Dram per Cubic foot (dr/ft3) is a unit of density.
Is the nanogram per pint to dram per cubic foot conversion exact?
Yes. Both nanogram per pint and dram per cubic foot are defined by fixed standards rather than physical artifacts, so the factor of 3.377505e-8 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.