Mass per volume density.
Nanograms per Pint to Grams per Cubic yard Converter — ng/pt to g/yd3
Convert Nanogram per Pint (ng/pt) to Gram per Cubic yard (g/yd3) using the exact conversion factor (1 nanogram per pint = 0.0000016158 gram per cubic yard). See the formula, worked examples, and conversion table.
Nanograms per Pint to Grams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2.11337642e-9 / 0.001307950619.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Nanograms per Pint to Grams per Cubic yard
Nanogram per Pint and Gram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
grams per cubic yard = nanograms per pint × 0.00000161579220779
This factor comes from each unit's defined relationship to the category's base unit: 1 nanogram per pint equals 2.113376e-9 base units, and 1 gram per cubic yard equals 0.00130795061931 base units, so dividing one by the other gives the direct nanogram per pint-to-gram per cubic yard factor of 0.00000161579220779.
Simple example
1 ng/pt × 0.000001615792208 = 0.0000016158 g/yd3
1 nanogram per pint = 0.0000016158 grams per cubic yard.
Real-world example
1,000 ng/pt × 0.000001615792208 = 0.0016157922 g/yd3
1,000 nanograms per pint = 0.0016157922 grams per cubic yard.
Conversion table
| Nanogram per Pint (ng/pt) | Gram per Cubic yard (g/yd3) |
|---|---|
| 0.1 ng/pt | 1.615792e-7 g/yd3 |
| 1 ng/pt | 0.0000016158 g/yd3 |
| 10 ng/pt | 0.0000161579 g/yd3 |
| 100 ng/pt | 0.0001615792 g/yd3 |
| 1,000 ng/pt | 0.0016157922 g/yd3 |
| 10,000 ng/pt | 0.0161579221 g/yd3 |
Reverse conversion: Gram per Cubic yard to Nanogram per Pint
0.0000016158 g/yd3 × 618891.4609 = 1.000004823 ng/pt
0.0000016158 grams per cubic yard = 1.000004823 nanograms per pint.
nanograms per pint = grams per cubic yard × 618891.460905
For a page dedicated to this direction, see Gram per Cubic yard to Nanogram per Pint.
Understanding the Nanogram per Pint (ng/pt)
Mass per volume density.
Understanding the Gram per Cubic yard (g/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many grams per cubic yard are in 1 nanogram per pint?
1 nanogram per pint equals 0.0000016158 grams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert nanogram per pint to gram per cubic yard?
Multiply the nanogram per pint value by 0.000001615792208. The converter above does this instantly to whatever precision you set.
How do I convert gram per cubic yard back to nanogram per pint?
Use the reverse factor: 1 gram per cubic yard equals 618,891.4609 nanograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a nanogram per pint?
Nanogram per Pint (ng/pt) is a unit of density.
What is a gram per cubic yard?
Gram per Cubic yard (g/yd3) is a unit of density.
Is the nanogram per pint to gram per cubic yard conversion exact?
Yes. Both nanogram per pint and gram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 0.000001615792208 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.