Mass per volume density.
Nanograms per Pint to Troy ounces per Liter Converter — ng/pt to oz t/L
Convert Nanogram per Pint (ng/pt) to Troy ounce per Liter (oz t/L) using the exact conversion factor (1 nanogram per pint = 6.794663e-11 troy ounce per liter). See the formula, worked examples, and conversion table.
Nanograms per Pint to Troy ounces per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 2.11337642e-9 / 31.1034768.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Nanograms per Pint to Troy ounces per Liter
Nanogram per Pint and Troy ounce per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
troy ounces per liter = nanograms per pint × 6.794663e-11
This factor comes from each unit's defined relationship to the category's base unit: 1 nanogram per pint equals 2.113376e-9 base units, and 1 troy ounce per liter equals 31.1034768 base units, so dividing one by the other gives the direct nanogram per pint-to-troy ounce per liter factor of 6.794663e-11.
Simple example
1 ng/pt × 6.794663e-11 = 6.794663e-11 oz t/L
1 nanogram per pint = 6.794663e-11 troy ounces per liter.
Real-world example
1,000 ng/pt × 6.794663e-11 = 6.794663e-8 oz t/L
1,000 nanograms per pint = 6.794663e-8 troy ounces per liter.
Conversion table
| Nanogram per Pint (ng/pt) | Troy ounce per Liter (oz t/L) |
|---|---|
| 0.1 ng/pt | 6.794663e-12 oz t/L |
| 1 ng/pt | 6.794663e-11 oz t/L |
| 10 ng/pt | 6.794663e-10 oz t/L |
| 100 ng/pt | 6.794663e-9 oz t/L |
| 1,000 ng/pt | 6.794663e-8 oz t/L |
| 10,000 ng/pt | 6.794663e-7 oz t/L |
Reverse conversion: Troy ounce per Liter to Nanogram per Pint
6.794663e-11 oz t/L × 14717433450 = 1.000000005 ng/pt
6.794663e-11 troy ounces per liter = 1.000000005 nanograms per pint.
nanograms per pint = troy ounces per liter × 14717433450.3
For a page dedicated to this direction, see Troy ounce per Liter to Nanogram per Pint.
Understanding the Nanogram per Pint (ng/pt)
Mass per volume density.
Understanding the Troy ounce per Liter (oz t/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many troy ounces per liter are in 1 nanogram per pint?
1 nanogram per pint equals 6.794663e-11 troy ounces per liter, using the exact defined conversion factor rather than an estimate.
How do I convert nanogram per pint to troy ounce per liter?
Multiply the nanogram per pint value by 6.794663e-11. The converter above does this instantly to whatever precision you set.
How do I convert troy ounce per liter back to nanogram per pint?
Use the reverse factor: 1 troy ounce per liter equals 14,717,433,450 nanograms per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a nanogram per pint?
Nanogram per Pint (ng/pt) is a unit of density.
What is a troy ounce per liter?
Troy ounce per Liter (oz t/L) is a unit of density.
Is the nanogram per pint to troy ounce per liter conversion exact?
Yes. Both nanogram per pint and troy ounce per liter are defined by fixed standards rather than physical artifacts, so the factor of 6.794663e-11 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.