Mass per volume density.
Nanograms per Quart to Drams per Cubic yard Converter — ng/qt to dr/yd3
Convert Nanogram per Quart (ng/qt) to Dram per Cubic yard (dr/yd3) using the exact conversion factor (1 nanogram per quart = 4.559631e-7 dram per cubic yard). See the formula, worked examples, and conversion table.
Nanograms per Quart to Drams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1.05668821e-9 / 0.002317486021.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Nanograms per Quart to Drams per Cubic yard
Nanogram per Quart and Dram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic yard = nanograms per quart × 4.559631e-7
This factor comes from each unit's defined relationship to the category's base unit: 1 nanogram per quart equals 1.056688e-9 base units, and 1 dram per cubic yard equals 0.00231748602054 base units, so dividing one by the other gives the direct nanogram per quart-to-dram per cubic yard factor of 4.559631e-7.
Simple example
1 ng/qt × 4.559631e-7 = 4.559631e-7 dr/yd3
1 nanogram per quart = 4.559631e-7 drams per cubic yard.
Real-world example
1,000 ng/qt × 4.559631e-7 = 0.0004559631 dr/yd3
1,000 nanograms per quart = 0.0004559631 drams per cubic yard.
Conversion table
| Nanogram per Quart (ng/qt) | Dram per Cubic yard (dr/yd3) |
|---|---|
| 0.1 ng/qt | 4.559631e-8 dr/yd3 |
| 1 ng/qt | 4.559631e-7 dr/yd3 |
| 10 ng/qt | 0.0000045596 dr/yd3 |
| 100 ng/qt | 0.0000455963 dr/yd3 |
| 1,000 ng/qt | 0.0004559631 dr/yd3 |
| 10,000 ng/qt | 0.0045596314 dr/yd3 |
Reverse conversion: Dram per Cubic yard to Nanogram per Quart
4.559631e-7 dr/yd3 × 2193159.723 = 0.999999906 ng/qt
4.559631e-7 drams per cubic yard = 0.999999906 nanograms per quart.
nanograms per quart = drams per cubic yard × 2193159.72285
For a page dedicated to this direction, see Dram per Cubic yard to Nanogram per Quart.
Understanding the Nanogram per Quart (ng/qt)
Mass per volume density.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic yard are in 1 nanogram per quart?
1 nanogram per quart equals 4.559631e-7 drams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert nanogram per quart to dram per cubic yard?
Multiply the nanogram per quart value by 4.559631e-7. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic yard back to nanogram per quart?
Use the reverse factor: 1 dram per cubic yard equals 2,193,159.723 nanograms per quart. You can also use the swap control in the converter above to flip the direction instantly.
What is a nanogram per quart?
Nanogram per Quart (ng/qt) is a unit of density.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
Is the nanogram per quart to dram per cubic yard conversion exact?
Yes. Both nanogram per quart and dram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 4.559631e-7 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.