Mass per volume density.
Ounces per Liter to Decagrams per Cubic foot Converter — oz/L to dag/ft3
Convert Ounce per Liter (oz/L) to Decagram per Cubic foot (dag/ft3) using the exact conversion factor (1 ounce per liter = 80.27690973 decagram per cubic foot). See the formula, worked examples, and conversion table.
Ounces per Liter to Decagrams per Cubic foot converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 28.34952313 / 0.3531466672.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Ounces per Liter to Decagrams per Cubic foot
Ounce per Liter and Decagram per Cubic foot both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
decagrams per cubic foot = ounces per liter × 80.2769097287
This factor comes from each unit's defined relationship to the category's base unit: 1 ounce per liter equals 28.349523125 base units, and 1 decagram per cubic foot equals 0.353146667215 base units, so dividing one by the other gives the direct ounce per liter-to-decagram per cubic foot factor of 80.2769097287.
Simple example
1 oz/L × 80.27690973 = 80.27690973 dag/ft3
1 ounce per liter = 80.27690973 decagrams per cubic foot.
Real-world example
1,000 oz/L × 80.27690973 = 80,276.90973 dag/ft3
1,000 ounces per liter = 80,276.90973 decagrams per cubic foot.
Conversion table
| Ounce per Liter (oz/L) | Decagram per Cubic foot (dag/ft3) |
|---|---|
| 0.1 oz/L | 8.027690973 dag/ft3 |
| 1 oz/L | 80.27690973 dag/ft3 |
| 10 oz/L | 802.7690973 dag/ft3 |
| 100 oz/L | 8,027.690973 dag/ft3 |
| 1,000 oz/L | 80,276.90973 dag/ft3 |
| 10,000 oz/L | 802,769.0973 dag/ft3 |
Reverse conversion: Decagram per Cubic foot to Ounce per Liter
80.27690973 dag/ft3 × 0.0124568821 = 1 oz/L
80.27690973 decagrams per cubic foot = 1 ounces per liter.
ounces per liter = decagrams per cubic foot × 0.012456882102
For a page dedicated to this direction, see Decagram per Cubic foot to Ounce per Liter.
Understanding the Ounce per Liter (oz/L)
Mass per volume density.
Understanding the Decagram per Cubic foot (dag/ft3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many decagrams per cubic foot are in 1 ounce per liter?
1 ounce per liter equals 80.27690973 decagrams per cubic foot, using the exact defined conversion factor rather than an estimate.
How do I convert ounce per liter to decagram per cubic foot?
Multiply the ounce per liter value by 80.27690973. The converter above does this instantly to whatever precision you set.
How do I convert decagram per cubic foot back to ounce per liter?
Use the reverse factor: 1 decagram per cubic foot equals 0.0124568821 ounces per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a ounce per liter?
Ounce per Liter (oz/L) is a unit of density.
What is a decagram per cubic foot?
Decagram per Cubic foot (dag/ft3) is a unit of density.
Is the ounce per liter to decagram per cubic foot conversion exact?
Yes. Both ounce per liter and decagram per cubic foot are defined by fixed standards rather than physical artifacts, so the factor of 80.27690973 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.