Mass per volume density.
Pounds per Cubic yard to Decagrams per Gallon Converter — lb/yd3 to dag/gal
Convert Pound per Cubic yard (lb/yd3) to Decagram per Gallon (dag/gal) using the exact conversion factor (1 pound per cubic yard = 0.2245795556 decagram per gallon). See the formula, worked examples, and conversion table.
Pounds per Cubic yard to Decagrams per Gallon converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 0.5932764213 / 2.641720524.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Cubic yard to Decagrams per Gallon
Pound per Cubic yard and Decagram per Gallon both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
decagrams per gallon = pounds per cubic yard × 0.22457955562
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per cubic yard equals 0.593276421258 base units, and 1 decagram per gallon equals 2.64172052358 base units, so dividing one by the other gives the direct pound per cubic yard-to-decagram per gallon factor of 0.22457955562.
Simple example
1 lb/yd3 × 0.2245795556 = 0.2245795556 dag/gal
1 pound per cubic yard = 0.2245795556 decagrams per gallon.
Real-world example
1,000 lb/yd3 × 0.2245795556 = 224.5795556 dag/gal
1,000 pounds per cubic yard = 224.5795556 decagrams per gallon.
Conversion table
| Pound per Cubic yard (lb/yd3) | Decagram per Gallon (dag/gal) |
|---|---|
| 0.1 lb/yd3 | 0.0224579556 dag/gal |
| 1 lb/yd3 | 0.2245795556 dag/gal |
| 10 lb/yd3 | 2.245795556 dag/gal |
| 100 lb/yd3 | 22.45795556 dag/gal |
| 1,000 lb/yd3 | 224.5795556 dag/gal |
| 10,000 lb/yd3 | 2,245.795556 dag/gal |
Reverse conversion: Decagram per Gallon to Pound per Cubic yard
0.2245795556 dag/gal × 4.452765067 = 0.9999999999 lb/yd3
0.2245795556 decagrams per gallon = 0.9999999999 pounds per cubic yard.
pounds per cubic yard = decagrams per gallon × 4.45276506688
For a page dedicated to this direction, see Decagram per Gallon to Pound per Cubic yard.
Understanding the Pound per Cubic yard (lb/yd3)
Mass per volume density.
Understanding the Decagram per Gallon (dag/gal)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many decagrams per gallon are in 1 pound per cubic yard?
1 pound per cubic yard equals 0.2245795556 decagrams per gallon, using the exact defined conversion factor rather than an estimate.
How do I convert pound per cubic yard to decagram per gallon?
Multiply the pound per cubic yard value by 0.2245795556. The converter above does this instantly to whatever precision you set.
How do I convert decagram per gallon back to pound per cubic yard?
Use the reverse factor: 1 decagram per gallon equals 4.452765067 pounds per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per cubic yard?
Pound per Cubic yard (lb/yd3) is a unit of density.
What is a decagram per gallon?
Decagram per Gallon (dag/gal) is a unit of density.
Is the pound per cubic yard to decagram per gallon conversion exact?
Yes. Both pound per cubic yard and decagram per gallon are defined by fixed standards rather than physical artifacts, so the factor of 0.2245795556 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.