Mass per volume density.
Pounds per Fluid ounce to Kilograms per Pint Converter — lb/fl oz to kg/pt
Convert Pound per Fluid ounce (lb/fl oz) to Kilogram per Pint (kg/pt) using the exact conversion factor (1 pound per fluid ounce = 7.25747792 kilogram per pint). See the formula, worked examples, and conversion table.
Pounds per Fluid ounce to Kilograms per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 15337.7827 / 2113.376419.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Fluid ounce to Kilograms per Pint
Pound per Fluid ounce and Kilogram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
kilograms per pint = pounds per fluid ounce × 7.25747792
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per fluid ounce equals 15337.7826966 base units, and 1 kilogram per pint equals 2113.37641887 base units, so dividing one by the other gives the direct pound per fluid ounce-to-kilogram per pint factor of 7.25747792.
Simple example
1 lb/fl oz × 7.25747792 = 7.25747792 kg/pt
1 pound per fluid ounce = 7.25747792 kilograms per pint.
Real-world example
1,000 lb/fl oz × 7.25747792 = 7,257.47792 kg/pt
1,000 pounds per fluid ounce = 7,257.47792 kilograms per pint.
Conversion table
| Pound per Fluid ounce (lb/fl oz) | Kilogram per Pint (kg/pt) |
|---|---|
| 0.1 lb/fl oz | 0.725747792 kg/pt |
| 1 lb/fl oz | 7.25747792 kg/pt |
| 10 lb/fl oz | 72.5747792 kg/pt |
| 100 lb/fl oz | 725.747792 kg/pt |
| 1,000 lb/fl oz | 7,257.47792 kg/pt |
| 10,000 lb/fl oz | 72,574.7792 kg/pt |
Reverse conversion: Kilogram per Pint to Pound per Fluid ounce
7.25747792 kg/pt × 0.1377889139 = 1 lb/fl oz
7.25747792 kilograms per pint = 1 pound per fluid ounce.
pounds per fluid ounce = kilograms per pint × 0.137788913866
For a page dedicated to this direction, see Kilogram per Pint to Pound per Fluid ounce.
Understanding the Pound per Fluid ounce (lb/fl oz)
Mass per volume density.
Understanding the Kilogram per Pint (kg/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many kilograms per pint are in 1 pound per fluid ounce?
1 pound per fluid ounce equals 7.25747792 kilograms per pint, using the exact defined conversion factor rather than an estimate.
How do I convert pound per fluid ounce to kilogram per pint?
Multiply the pound per fluid ounce value by 7.25747792. The converter above does this instantly to whatever precision you set.
How do I convert kilogram per pint back to pound per fluid ounce?
Use the reverse factor: 1 kilogram per pint equals 0.1377889139 pounds per fluid ounce. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per fluid ounce?
Pound per Fluid ounce (lb/fl oz) is a unit of density.
What is a kilogram per pint?
Kilogram per Pint (kg/pt) is a unit of density.
Is the pound per fluid ounce to kilogram per pint conversion exact?
Yes. Both pound per fluid ounce and kilogram per pint are defined by fixed standards rather than physical artifacts, so the factor of 7.25747792 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.