Mass per volume density.
Pounds per Imperial gallon to Carats per Liter Converter — lb/imp gal to ct/L
Convert Pound per Imperial gallon (lb/imp gal) to Carat per Liter (ct/L) using the exact conversion factor (1 pound per imperial gallon = 498.8818633 carat per liter). See the formula, worked examples, and conversion table.
Pounds per Imperial gallon to Carats per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 99.77637266 / 0.2.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Imperial gallon to Carats per Liter
Pound per Imperial gallon and Carat per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
carats per liter = pounds per imperial gallon × 498.881863316
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per imperial gallon equals 99.7763726631 base units, and 1 carat per liter equals 0.2 base units, so dividing one by the other gives the direct pound per imperial gallon-to-carat per liter factor of 498.881863316.
Simple example
1 lb/imp gal × 498.8818633 = 498.8818633 ct/L
1 pound per imperial gallon = 498.8818633 carats per liter.
Real-world example
1,000 lb/imp gal × 498.8818633 = 498,881.8633 ct/L
1,000 pounds per imperial gallon = 498,881.8633 carats per liter.
Conversion table
| Pound per Imperial gallon (lb/imp gal) | Carat per Liter (ct/L) |
|---|---|
| 0.1 lb/imp gal | 49.88818633 ct/L |
| 1 lb/imp gal | 498.8818633 ct/L |
| 10 lb/imp gal | 4,988.818633 ct/L |
| 100 lb/imp gal | 49,888.18633 ct/L |
| 1,000 lb/imp gal | 498,881.8633 ct/L |
| 10,000 lb/imp gal | 4,988,818.633 ct/L |
Reverse conversion: Carat per Liter to Pound per Imperial gallon
498.8818633 ct/L × 0.002004482571 = 1 lb/imp gal
498.8818633 carats per liter = 1 pounds per imperial gallon.
pounds per imperial gallon = carats per liter × 0.00200448257099
For a page dedicated to this direction, see Carat per Liter to Pound per Imperial gallon.
Understanding the Pound per Imperial gallon (lb/imp gal)
Mass per volume density.
Understanding the Carat per Liter (ct/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many carats per liter are in 1 pound per imperial gallon?
1 pound per imperial gallon equals 498.8818633 carats per liter, using the exact defined conversion factor rather than an estimate.
How do I convert pound per imperial gallon to carat per liter?
Multiply the pound per imperial gallon value by 498.8818633. The converter above does this instantly to whatever precision you set.
How do I convert carat per liter back to pound per imperial gallon?
Use the reverse factor: 1 carat per liter equals 0.0020044826 pounds per imperial gallon. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per imperial gallon?
Pound per Imperial gallon (lb/imp gal) is a unit of density.
What is a carat per liter?
Carat per Liter (ct/L) is a unit of density.
Is the pound per imperial gallon to carat per liter conversion exact?
Yes. Both pound per imperial gallon and carat per liter are defined by fixed standards rather than physical artifacts, so the factor of 498.8818633 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.