Mass per volume density.
Pounds per Imperial gallon to Drams per Quart Converter — lb/imp gal to dr/qt
Convert Pound per Imperial gallon (lb/imp gal) to Dram per Quart (dr/qt) using the exact conversion factor (1 pound per imperial gallon = 53.29114782 dram per quart). See the formula, worked examples, and conversion table.
Pounds per Imperial gallon to Drams per Quart converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 99.77637266 / 1.872287927.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Imperial gallon to Drams per Quart
Pound per Imperial gallon and Dram per Quart both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per quart = pounds per imperial gallon × 53.2911478163
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per imperial gallon equals 99.7763726631 base units, and 1 dram per quart equals 1.87228792683 base units, so dividing one by the other gives the direct pound per imperial gallon-to-dram per quart factor of 53.2911478163.
Simple example
1 lb/imp gal × 53.29114782 = 53.29114782 dr/qt
1 pound per imperial gallon = 53.29114782 drams per quart.
Real-world example
1,000 lb/imp gal × 53.29114782 = 53,291.14782 dr/qt
1,000 pounds per imperial gallon = 53,291.14782 drams per quart.
Conversion table
| Pound per Imperial gallon (lb/imp gal) | Dram per Quart (dr/qt) |
|---|---|
| 0.1 lb/imp gal | 5.329114782 dr/qt |
| 1 lb/imp gal | 53.29114782 dr/qt |
| 10 lb/imp gal | 532.9114782 dr/qt |
| 100 lb/imp gal | 5,329.114782 dr/qt |
| 1,000 lb/imp gal | 53,291.14782 dr/qt |
| 10,000 lb/imp gal | 532,911.4782 dr/qt |
Reverse conversion: Dram per Quart to Pound per Imperial gallon
53.29114782 dr/qt × 0.01876484259 = 1 lb/imp gal
53.29114782 drams per quart = 1 pounds per imperial gallon.
pounds per imperial gallon = drams per quart × 0.018764842586
For a page dedicated to this direction, see Dram per Quart to Pound per Imperial gallon.
Understanding the Pound per Imperial gallon (lb/imp gal)
Mass per volume density.
Understanding the Dram per Quart (dr/qt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per quart are in 1 pound per imperial gallon?
1 pound per imperial gallon equals 53.29114782 drams per quart, using the exact defined conversion factor rather than an estimate.
How do I convert pound per imperial gallon to dram per quart?
Multiply the pound per imperial gallon value by 53.29114782. The converter above does this instantly to whatever precision you set.
How do I convert dram per quart back to pound per imperial gallon?
Use the reverse factor: 1 dram per quart equals 0.0187648426 pounds per imperial gallon. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per imperial gallon?
Pound per Imperial gallon (lb/imp gal) is a unit of density.
What is a dram per quart?
Dram per Quart (dr/qt) is a unit of density.
Is the pound per imperial gallon to dram per quart conversion exact?
Yes. Both pound per imperial gallon and dram per quart are defined by fixed standards rather than physical artifacts, so the factor of 53.29114782 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.