Mass per volume density.
Pounds per Teaspoon to Drams per Cubic foot Converter — lb/tsp to dr/ft3
Convert Pound per Teaspoon (lb/tsp) to Dram per Cubic foot (dr/ft3) using the exact conversion factor (1 pound per teaspoon = 1,470,729.974 dram per cubic foot). See the formula, worked examples, and conversion table.
Pounds per Teaspoon to Drams per Cubic foot converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 92026.69618 / 0.06257212255.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Teaspoon to Drams per Cubic foot
Pound per Teaspoon and Dram per Cubic foot both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic foot = pounds per teaspoon × 1470729.97403
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per teaspoon equals 92026.6961794 base units, and 1 dram per cubic foot equals 0.0625721225545 base units, so dividing one by the other gives the direct pound per teaspoon-to-dram per cubic foot factor of 1470729.97403.
Simple example
1 lb/tsp × 1470729.974 = 1,470,729.974 dr/ft3
1 pound per teaspoon = 1,470,729.974 drams per cubic foot.
Real-world example
1,000 lb/tsp × 1470729.974 = 1,470,729,974 dr/ft3
1,000 pounds per teaspoon = 1,470,729,974 drams per cubic foot.
Conversion table
| Pound per Teaspoon (lb/tsp) | Dram per Cubic foot (dr/ft3) |
|---|---|
| 0.1 lb/tsp | 147,072.9974 dr/ft3 |
| 1 lb/tsp | 1,470,729.974 dr/ft3 |
| 10 lb/tsp | 14,707,299.74 dr/ft3 |
| 100 lb/tsp | 147,072,997.4 dr/ft3 |
| 1,000 lb/tsp | 1,470,729,974 dr/ft3 |
| 10,000 lb/tsp | 14,707,299,740 dr/ft3 |
Reverse conversion: Dram per Cubic foot to Pound per Teaspoon
1 dr/ft3 × 6.799345e-7 = 6.799345e-7 lb/tsp
1 dram per cubic foot = 6.799345e-7 pounds per teaspoon.
pounds per teaspoon = drams per cubic foot × 6.799345e-7
For a page dedicated to this direction, see Dram per Cubic foot to Pound per Teaspoon.
Understanding the Pound per Teaspoon (lb/tsp)
Mass per volume density.
Understanding the Dram per Cubic foot (dr/ft3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic foot are in 1 pound per teaspoon?
1 pound per teaspoon equals 1,470,729.974 drams per cubic foot, using the exact defined conversion factor rather than an estimate.
How do I convert pound per teaspoon to dram per cubic foot?
Multiply the pound per teaspoon value by 1470729.974. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic foot back to pound per teaspoon?
Use the reverse factor: 1 dram per cubic foot equals 6.799345e-7 pounds per teaspoon. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per teaspoon?
Pound per Teaspoon (lb/tsp) is a unit of density.
What is a dram per cubic foot?
Dram per Cubic foot (dr/ft3) is a unit of density.
Is the pound per teaspoon to dram per cubic foot conversion exact?
Yes. Both pound per teaspoon and dram per cubic foot are defined by fixed standards rather than physical artifacts, so the factor of 1470729.974 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.