Mass per volume density.
Pounds per Teaspoon to Drams per Cubic yard Converter — lb/tsp to dr/yd3
Convert Pound per Teaspoon (lb/tsp) to Dram per Cubic yard (dr/yd3) using the exact conversion factor (1 pound per teaspoon = 39,709,709.3 dram per cubic yard). See the formula, worked examples, and conversion table.
Pounds per Teaspoon to Drams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 92026.69618 / 0.002317486021.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Pounds per Teaspoon to Drams per Cubic yard
Pound per Teaspoon and Dram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic yard = pounds per teaspoon × 39709709.2987
This factor comes from each unit's defined relationship to the category's base unit: 1 pound per teaspoon equals 92026.6961794 base units, and 1 dram per cubic yard equals 0.00231748602054 base units, so dividing one by the other gives the direct pound per teaspoon-to-dram per cubic yard factor of 39709709.2987.
Simple example
1 lb/tsp × 39709709.3 = 39,709,709.3 dr/yd3
1 pound per teaspoon = 39,709,709.3 drams per cubic yard.
Real-world example
1,000 lb/tsp × 39709709.3 = 39,709,709,300 dr/yd3
1,000 pounds per teaspoon = 39,709,709,300 drams per cubic yard.
Conversion table
| Pound per Teaspoon (lb/tsp) | Dram per Cubic yard (dr/yd3) |
|---|---|
| 0.1 lb/tsp | 3,970,970.93 dr/yd3 |
| 1 lb/tsp | 39,709,709.3 dr/yd3 |
| 10 lb/tsp | 397,097,093 dr/yd3 |
| 100 lb/tsp | 3,970,970,930 dr/yd3 |
| 1,000 lb/tsp | 39,709,709,300 dr/yd3 |
| 10,000 lb/tsp | 397,097,093,000 dr/yd3 |
Reverse conversion: Dram per Cubic yard to Pound per Teaspoon
1 dr/yd3 × 2.518276e-8 = 2.518276e-8 lb/tsp
1 dram per cubic yard = 2.518276e-8 pounds per teaspoon.
pounds per teaspoon = drams per cubic yard × 2.518276e-8
For a page dedicated to this direction, see Dram per Cubic yard to Pound per Teaspoon.
Understanding the Pound per Teaspoon (lb/tsp)
Mass per volume density.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic yard are in 1 pound per teaspoon?
1 pound per teaspoon equals 39,709,709.3 drams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert pound per teaspoon to dram per cubic yard?
Multiply the pound per teaspoon value by 39709709.3. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic yard back to pound per teaspoon?
Use the reverse factor: 1 dram per cubic yard equals 2.518276e-8 pounds per teaspoon. You can also use the swap control in the converter above to flip the direction instantly.
What is a pound per teaspoon?
Pound per Teaspoon (lb/tsp) is a unit of density.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
Is the pound per teaspoon to dram per cubic yard conversion exact?
Yes. Both pound per teaspoon and dram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 39709709.3 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.