Mass per volume density.
Stones per Cubic yard to Drams per Oil barrel Converter — st/yd3 to dr/bbl
Convert Stone per Cubic yard (st/yd3) to Dram per Oil barrel (dr/bbl) using the exact conversion factor (1 stone per cubic yard = 745.2839506 dram per oil barrel). See the formula, worked examples, and conversion table.
Stones per Cubic yard to Drams per Oil barrel converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 8.305869898 / 0.01114457099.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Stones per Cubic yard to Drams per Oil barrel
Stone per Cubic yard and Dram per Oil barrel both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per oil barrel = stones per cubic yard × 745.283950617
This factor comes from each unit's defined relationship to the category's base unit: 1 stone per cubic yard equals 8.30586989761 base units, and 1 dram per oil barrel equals 0.011144570993 base units, so dividing one by the other gives the direct stone per cubic yard-to-dram per oil barrel factor of 745.283950617.
Simple example
1 st/yd3 × 745.2839506 = 745.2839506 dr/bbl
1 stone per cubic yard = 745.2839506 drams per oil barrel.
Real-world example
1,000 st/yd3 × 745.2839506 = 745,283.9506 dr/bbl
1,000 stones per cubic yard = 745,283.9506 drams per oil barrel.
Conversion table
| Stone per Cubic yard (st/yd3) | Dram per Oil barrel (dr/bbl) |
|---|---|
| 0.1 st/yd3 | 74.52839506 dr/bbl |
| 1 st/yd3 | 745.2839506 dr/bbl |
| 10 st/yd3 | 7,452.839506 dr/bbl |
| 100 st/yd3 | 74,528.39506 dr/bbl |
| 1,000 st/yd3 | 745,283.9506 dr/bbl |
| 10,000 st/yd3 | 7,452,839.506 dr/bbl |
Reverse conversion: Dram per Oil barrel to Stone per Cubic yard
745.2839506 dr/bbl × 0.001341770474 = 1 st/yd3
745.2839506 drams per oil barrel = 1 stones per cubic yard.
stones per cubic yard = drams per oil barrel × 0.00134177047442
For a page dedicated to this direction, see Dram per Oil barrel to Stone per Cubic yard.
Understanding the Stone per Cubic yard (st/yd3)
Mass per volume density.
Understanding the Dram per Oil barrel (dr/bbl)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per oil barrel are in 1 stone per cubic yard?
1 stone per cubic yard equals 745.2839506 drams per oil barrel, using the exact defined conversion factor rather than an estimate.
How do I convert stone per cubic yard to dram per oil barrel?
Multiply the stone per cubic yard value by 745.2839506. The converter above does this instantly to whatever precision you set.
How do I convert dram per oil barrel back to stone per cubic yard?
Use the reverse factor: 1 dram per oil barrel equals 0.0013417705 stones per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a stone per cubic yard?
Stone per Cubic yard (st/yd3) is a unit of density.
What is a dram per oil barrel?
Dram per Oil barrel (dr/bbl) is a unit of density.
Is the stone per cubic yard to dram per oil barrel conversion exact?
Yes. Both stone per cubic yard and dram per oil barrel are defined by fixed standards rather than physical artifacts, so the factor of 745.2839506 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.