Mass per volume density.
Stones per Imperial gallon to Drams per Quart Converter — st/imp gal to dr/qt
Convert Stone per Imperial gallon (st/imp gal) to Dram per Quart (dr/qt) using the exact conversion factor (1 stone per imperial gallon = 746.0760694 dram per quart). See the formula, worked examples, and conversion table.
Stones per Imperial gallon to Drams per Quart converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 1396.869217 / 1.872287927.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Stones per Imperial gallon to Drams per Quart
Stone per Imperial gallon and Dram per Quart both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per quart = stones per imperial gallon × 746.076069428
This factor comes from each unit's defined relationship to the category's base unit: 1 stone per imperial gallon equals 1396.86921728 base units, and 1 dram per quart equals 1.87228792683 base units, so dividing one by the other gives the direct stone per imperial gallon-to-dram per quart factor of 746.076069428.
Simple example
1 st/imp gal × 746.0760694 = 746.0760694 dr/qt
1 stone per imperial gallon = 746.0760694 drams per quart.
Real-world example
1,000 st/imp gal × 746.0760694 = 746,076.0694 dr/qt
1,000 stones per imperial gallon = 746,076.0694 drams per quart.
Conversion table
| Stone per Imperial gallon (st/imp gal) | Dram per Quart (dr/qt) |
|---|---|
| 0.1 st/imp gal | 74.60760694 dr/qt |
| 1 st/imp gal | 746.0760694 dr/qt |
| 10 st/imp gal | 7,460.760694 dr/qt |
| 100 st/imp gal | 74,607.60694 dr/qt |
| 1,000 st/imp gal | 746,076.0694 dr/qt |
| 10,000 st/imp gal | 7,460,760.694 dr/qt |
Reverse conversion: Dram per Quart to Stone per Imperial gallon
746.0760694 dr/qt × 0.001340345899 = 1 st/imp gal
746.0760694 drams per quart = 1 stones per imperial gallon.
stones per imperial gallon = drams per quart × 0.001340345899
For a page dedicated to this direction, see Dram per Quart to Stone per Imperial gallon.
Understanding the Stone per Imperial gallon (st/imp gal)
Mass per volume density.
Understanding the Dram per Quart (dr/qt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per quart are in 1 stone per imperial gallon?
1 stone per imperial gallon equals 746.0760694 drams per quart, using the exact defined conversion factor rather than an estimate.
How do I convert stone per imperial gallon to dram per quart?
Multiply the stone per imperial gallon value by 746.0760694. The converter above does this instantly to whatever precision you set.
How do I convert dram per quart back to stone per imperial gallon?
Use the reverse factor: 1 dram per quart equals 0.0013403459 stones per imperial gallon. You can also use the swap control in the converter above to flip the direction instantly.
What is a stone per imperial gallon?
Stone per Imperial gallon (st/imp gal) is a unit of density.
What is a dram per quart?
Dram per Quart (dr/qt) is a unit of density.
Is the stone per imperial gallon to dram per quart conversion exact?
Yes. Both stone per imperial gallon and dram per quart are defined by fixed standards rather than physical artifacts, so the factor of 746.0760694 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.