Stones per Liter to Grams per Teaspoon Converter — st/L to g/tsp

Convert Stone per Liter (st/L) to Gram per Teaspoon (g/tsp) using the exact conversion factor (1 stone per liter = 31.30009718 gram per teaspoon). See the formula, worked examples, and conversion table.

Stones per Liter to Grams per Teaspoon converter

Converter

Density Converter

Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.

Result 1 stone per liter = 31.30009718 gram per teaspoon
Advertisement Converter ad slot

Reserved below the result so the calculator remains usable.

From definition

Mass per volume density.

To definition

Mass per volume density.

Formula

Result = input x 6350.29318 / 202.8841362.

Density uses kilograms per cubic meter as the base unit.

Advertisement Ad slot: content top (728x90)

Reserved above the conversion cards and below the converter.

About Converting Stones per Liter to Grams per Teaspoon

Stone per Liter and Gram per Teaspoon both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.

Formula

grams per teaspoon = stones per liter × 31.3000971815

This factor comes from each unit's defined relationship to the category's base unit: 1 stone per liter equals 6350.29318 base units, and 1 gram per teaspoon equals 202.884136211 base units, so dividing one by the other gives the direct stone per liter-to-gram per teaspoon factor of 31.3000971815.

Simple example

1 st/L × 31.30009718 = 31.30009718 g/tsp

1 stone per liter = 31.30009718 grams per teaspoon.

Real-world example

1,000 st/L × 31.30009718 = 31,300.09718 g/tsp

1,000 stones per liter = 31,300.09718 grams per teaspoon.

Conversion table

Stone per Liter (st/L)Gram per Teaspoon (g/tsp)
0.1 st/L3.130009718 g/tsp
1 st/L31.30009718 g/tsp
10 st/L313.0009718 g/tsp
100 st/L3,130.009718 g/tsp
1,000 st/L31,300.09718 g/tsp
10,000 st/L313,000.9718 g/tsp

Reverse conversion: Gram per Teaspoon to Stone per Liter

31.30009718 g/tsp × 0.03194878259 = 1 st/L

31.30009718 grams per teaspoon = 1 stones per liter.

stones per liter = grams per teaspoon × 0.0319487825932

For a page dedicated to this direction, see Gram per Teaspoon to Stone per Liter.

Understanding the Stone per Liter (st/L)

Mass per volume density.

Understanding the Gram per Teaspoon (g/tsp)

Mass per volume density.

Advertisement Ad slot: content middle (728x90)

Reserved between the cards and the FAQ so the page stays balanced.

Frequently asked questions

How many grams per teaspoon are in 1 stone per liter?

1 stone per liter equals 31.30009718 grams per teaspoon, using the exact defined conversion factor rather than an estimate.

How do I convert stone per liter to gram per teaspoon?

Multiply the stone per liter value by 31.30009718. The converter above does this instantly to whatever precision you set.

How do I convert gram per teaspoon back to stone per liter?

Use the reverse factor: 1 gram per teaspoon equals 0.0319487826 stones per liter. You can also use the swap control in the converter above to flip the direction instantly.

What is a stone per liter?

Stone per Liter (st/L) is a unit of density.

What is a gram per teaspoon?

Gram per Teaspoon (g/tsp) is a unit of density.

Is the stone per liter to gram per teaspoon conversion exact?

Yes. Both stone per liter and gram per teaspoon are defined by fixed standards rather than physical artifacts, so the factor of 31.30009718 used above is exact to as many digits as you choose to display.

What's the difference between density and mass concentration?

Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.