Mass per volume density.
Stones per Liter to Slugs per Imperial gallon Converter — st/L to slug/imp gal
Convert Stone per Liter (st/L) to Slug per Imperial gallon (slug/imp gal) using the exact conversion factor (1 stone per liter = 1.978155155 slug per imperial gallon). See the formula, worked examples, and conversion table.
Stones per Liter to Slugs per Imperial gallon converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 6350.29318 / 3210.209859.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Stones per Liter to Slugs per Imperial gallon
Stone per Liter and Slug per Imperial gallon both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
slugs per imperial gallon = stones per liter × 1.97815515472
This factor comes from each unit's defined relationship to the category's base unit: 1 stone per liter equals 6350.29318 base units, and 1 slug per imperial gallon equals 3210.20985885 base units, so dividing one by the other gives the direct stone per liter-to-slug per imperial gallon factor of 1.97815515472.
Simple example
1 st/L × 1.978155155 = 1.978155155 slug/imp gal
1 stone per liter = 1.978155155 slugs per imperial gallon.
Real-world example
1,000 st/L × 1.978155155 = 1,978.155155 slug/imp gal
1,000 stones per liter = 1,978.155155 slugs per imperial gallon.
Conversion table
| Stone per Liter (st/L) | Slug per Imperial gallon (slug/imp gal) |
|---|---|
| 0.1 st/L | 0.1978155155 slug/imp gal |
| 1 st/L | 1.978155155 slug/imp gal |
| 10 st/L | 19.78155155 slug/imp gal |
| 100 st/L | 197.8155155 slug/imp gal |
| 1,000 st/L | 1,978.155155 slug/imp gal |
| 10,000 st/L | 19,781.55155 slug/imp gal |
Reverse conversion: Slug per Imperial gallon to Stone per Liter
1.978155155 slug/imp gal × 0.5055215197 = 1 st/L
1.978155155 slugs per imperial gallon = 1 stones per liter.
stones per liter = slugs per imperial gallon × 0.505521519692
For a page dedicated to this direction, see Slug per Imperial gallon to Stone per Liter.
Understanding the Stone per Liter (st/L)
Mass per volume density.
Understanding the Slug per Imperial gallon (slug/imp gal)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many slugs per imperial gallon are in 1 stone per liter?
1 stone per liter equals 1.978155155 slugs per imperial gallon, using the exact defined conversion factor rather than an estimate.
How do I convert stone per liter to slug per imperial gallon?
Multiply the stone per liter value by 1.978155155. The converter above does this instantly to whatever precision you set.
How do I convert slug per imperial gallon back to stone per liter?
Use the reverse factor: 1 slug per imperial gallon equals 0.5055215197 stones per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a stone per liter?
Stone per Liter (st/L) is a unit of density.
What is a slug per imperial gallon?
Slug per Imperial gallon (slug/imp gal) is a unit of density.
Is the stone per liter to slug per imperial gallon conversion exact?
Yes. Both stone per liter and slug per imperial gallon are defined by fixed standards rather than physical artifacts, so the factor of 1.978155155 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.