Mass per volume density.
Metric tons per Cubic yard to Drams per Pint Converter — t/yd3 to dr/pt
Convert Metric ton per Cubic yard (t/yd3) to Dram per Pint (dr/pt) using the exact conversion factor (1 metric ton per cubic yard = 349.2920615 dram per pint). See the formula, worked examples, and conversion table.
Metric tons per Cubic yard to Drams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 1307.950619 / 3.744575854.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Metric tons per Cubic yard to Drams per Pint
Metric ton per Cubic yard and Dram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per pint = metric tons per cubic yard × 349.292061486
This factor comes from each unit's defined relationship to the category's base unit: 1 metric ton per cubic yard equals 1307.95061931 base units, and 1 dram per pint equals 3.74457585365 base units, so dividing one by the other gives the direct metric ton per cubic yard-to-dram per pint factor of 349.292061486.
Simple example
1 t/yd3 × 349.2920615 = 349.2920615 dr/pt
1 metric ton per cubic yard = 349.2920615 drams per pint.
Real-world example
1,000 t/yd3 × 349.2920615 = 349,292.0615 dr/pt
1,000 metric tons per cubic yard = 349,292.0615 drams per pint.
Conversion table
| Metric ton per Cubic yard (t/yd3) | Dram per Pint (dr/pt) |
|---|---|
| 0.1 t/yd3 | 34.92920615 dr/pt |
| 1 t/yd3 | 349.2920615 dr/pt |
| 10 t/yd3 | 3,492.920615 dr/pt |
| 100 t/yd3 | 34,929.20615 dr/pt |
| 1,000 t/yd3 | 349,292.0615 dr/pt |
| 10,000 t/yd3 | 3,492,920.615 dr/pt |
Reverse conversion: Dram per Pint to Metric ton per Cubic yard
349.2920615 dr/pt × 0.00286293366 = 1 t/yd3
349.2920615 drams per pint = 1 metric tons per cubic yard.
metric tons per cubic yard = drams per pint × 0.00286293366
For a page dedicated to this direction, see Dram per Pint to Metric ton per Cubic yard.
Understanding the Metric ton per Cubic yard (t/yd3)
Mass per volume density.
Understanding the Dram per Pint (dr/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per pint are in 1 metric ton per cubic yard?
1 metric ton per cubic yard equals 349.2920615 drams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert metric ton per cubic yard to dram per pint?
Multiply the metric ton per cubic yard value by 349.2920615. The converter above does this instantly to whatever precision you set.
How do I convert dram per pint back to metric ton per cubic yard?
Use the reverse factor: 1 dram per pint equals 0.0028629337 metric tons per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a metric ton per cubic yard?
Metric ton per Cubic yard (t/yd3) is a unit of density.
What is a dram per pint?
Dram per Pint (dr/pt) is a unit of density.
Is the metric ton per cubic yard to dram per pint conversion exact?
Yes. Both metric ton per cubic yard and dram per pint are defined by fixed standards rather than physical artifacts, so the factor of 349.2920615 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.