Mass per volume density.
Troy ounces per Cubic yard to Grams per Pint Converter — oz t/yd3 to g/pt
Convert Troy ounce per Cubic yard (oz t/yd3) to Gram per Pint (g/pt) using the exact conversion factor (1 troy ounce per cubic yard = 0.0192496762 gram per pint). See the formula, worked examples, and conversion table.
Troy ounces per Cubic yard to Grams per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 0.04068181174 / 2.113376419.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Cubic yard to Grams per Pint
Troy ounce per Cubic yard and Gram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
grams per pint = troy ounces per cubic yard × 0.019249676196
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per cubic yard equals 0.0406818117434 base units, and 1 gram per pint equals 2.11337641887 base units, so dividing one by the other gives the direct troy ounce per cubic yard-to-gram per pint factor of 0.019249676196.
Simple example
1 oz t/yd3 × 0.0192496762 = 0.0192496762 g/pt
1 troy ounce per cubic yard = 0.0192496762 grams per pint.
Real-world example
1,000 oz t/yd3 × 0.0192496762 = 19.2496762 g/pt
1,000 troy ounces per cubic yard = 19.2496762 grams per pint.
Conversion table
| Troy ounce per Cubic yard (oz t/yd3) | Gram per Pint (g/pt) |
|---|---|
| 0.1 oz t/yd3 | 0.0019249676 g/pt |
| 1 oz t/yd3 | 0.0192496762 g/pt |
| 10 oz t/yd3 | 0.192496762 g/pt |
| 100 oz t/yd3 | 1.92496762 g/pt |
| 1,000 oz t/yd3 | 19.2496762 g/pt |
| 10,000 oz t/yd3 | 192.496762 g/pt |
Reverse conversion: Gram per Pint to Troy ounce per Cubic yard
0.0192496762 g/pt × 51.94892578 = 1 oz t/yd3
0.0192496762 grams per pint = 1 troy ounces per cubic yard.
troy ounces per cubic yard = grams per pint × 51.9489257803
For a page dedicated to this direction, see Gram per Pint to Troy ounce per Cubic yard.
Understanding the Troy ounce per Cubic yard (oz t/yd3)
Mass per volume density.
Understanding the Gram per Pint (g/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many grams per pint are in 1 troy ounce per cubic yard?
1 troy ounce per cubic yard equals 0.0192496762 grams per pint, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per cubic yard to gram per pint?
Multiply the troy ounce per cubic yard value by 0.0192496762. The converter above does this instantly to whatever precision you set.
How do I convert gram per pint back to troy ounce per cubic yard?
Use the reverse factor: 1 gram per pint equals 51.94892578 troy ounces per cubic yard. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per cubic yard?
Troy ounce per Cubic yard (oz t/yd3) is a unit of density.
What is a gram per pint?
Gram per Pint (g/pt) is a unit of density.
Is the troy ounce per cubic yard to gram per pint conversion exact?
Yes. Both troy ounce per cubic yard and gram per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.0192496762 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.