Mass per volume density.
Troy ounces per Gallon to Drams per Cubic yard Converter — oz t/gal to dr/yd3
Convert Troy ounce per Gallon (oz t/gal) to Dram per Cubic yard (dr/yd3) using the exact conversion factor (1 troy ounce per gallon = 3,545.509759 dram per cubic yard). See the formula, worked examples, and conversion table.
Troy ounces per Gallon to Drams per Cubic yard converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 8.216669302 / 0.002317486021.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Gallon to Drams per Cubic yard
Troy ounce per Gallon and Dram per Cubic yard both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
drams per cubic yard = troy ounces per gallon × 3545.50975881
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per gallon equals 8.21666930173 base units, and 1 dram per cubic yard equals 0.00231748602054 base units, so dividing one by the other gives the direct troy ounce per gallon-to-dram per cubic yard factor of 3545.50975881.
Simple example
1 oz t/gal × 3545.509759 = 3,545.509759 dr/yd3
1 troy ounce per gallon = 3,545.509759 drams per cubic yard.
Real-world example
1,000 oz t/gal × 3545.509759 = 3,545,509.759 dr/yd3
1,000 troy ounces per gallon = 3,545,509.759 drams per cubic yard.
Conversion table
| Troy ounce per Gallon (oz t/gal) | Dram per Cubic yard (dr/yd3) |
|---|---|
| 0.1 oz t/gal | 354.5509759 dr/yd3 |
| 1 oz t/gal | 3,545.509759 dr/yd3 |
| 10 oz t/gal | 35,455.09759 dr/yd3 |
| 100 oz t/gal | 354,550.9759 dr/yd3 |
| 1,000 oz t/gal | 3,545,509.759 dr/yd3 |
| 10,000 oz t/gal | 35,455,097.59 dr/yd3 |
Reverse conversion: Dram per Cubic yard to Troy ounce per Gallon
1 dr/yd3 × 0.0002820468897 = 0.0002820469 oz t/gal
1 dram per cubic yard = 0.0002820469 troy ounces per gallon.
troy ounces per gallon = drams per cubic yard × 0.000282046889736
For a page dedicated to this direction, see Dram per Cubic yard to Troy ounce per Gallon.
Understanding the Troy ounce per Gallon (oz t/gal)
Mass per volume density.
Understanding the Dram per Cubic yard (dr/yd3)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many drams per cubic yard are in 1 troy ounce per gallon?
1 troy ounce per gallon equals 3,545.509759 drams per cubic yard, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per gallon to dram per cubic yard?
Multiply the troy ounce per gallon value by 3545.509759. The converter above does this instantly to whatever precision you set.
How do I convert dram per cubic yard back to troy ounce per gallon?
Use the reverse factor: 1 dram per cubic yard equals 0.0002820469 troy ounces per gallon. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per gallon?
Troy ounce per Gallon (oz t/gal) is a unit of density.
What is a dram per cubic yard?
Dram per Cubic yard (dr/yd3) is a unit of density.
Is the troy ounce per gallon to dram per cubic yard conversion exact?
Yes. Both troy ounce per gallon and dram per cubic yard are defined by fixed standards rather than physical artifacts, so the factor of 3545.509759 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.