Mass per volume density.
Troy ounces per Liter to Decagrams per Quart Converter — oz t/L to dag/qt
Convert Troy ounce per Liter (oz t/L) to Decagram per Quart (dag/qt) using the exact conversion factor (1 troy ounce per liter = 2.94348669 decagram per quart). See the formula, worked examples, and conversion table.
Troy ounces per Liter to Decagrams per Quart converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 31.1034768 / 10.56688209.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Liter to Decagrams per Quart
Troy ounce per Liter and Decagram per Quart both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
decagrams per quart = troy ounces per liter × 2.94348669005
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per liter equals 31.1034768 base units, and 1 decagram per quart equals 10.5668820943 base units, so dividing one by the other gives the direct troy ounce per liter-to-decagram per quart factor of 2.94348669005.
Simple example
1 oz t/L × 2.94348669 = 2.94348669 dag/qt
1 troy ounce per liter = 2.94348669 decagrams per quart.
Real-world example
1,000 oz t/L × 2.94348669 = 2,943.48669 dag/qt
1,000 troy ounces per liter = 2,943.48669 decagrams per quart.
Conversion table
| Troy ounce per Liter (oz t/L) | Decagram per Quart (dag/qt) |
|---|---|
| 0.1 oz t/L | 0.294348669 dag/qt |
| 1 oz t/L | 2.94348669 dag/qt |
| 10 oz t/L | 29.4348669 dag/qt |
| 100 oz t/L | 294.348669 dag/qt |
| 1,000 oz t/L | 2,943.48669 dag/qt |
| 10,000 oz t/L | 29,434.8669 dag/qt |
Reverse conversion: Decagram per Quart to Troy ounce per Liter
2.94348669 dag/qt × 0.3397331482 = 1 oz t/L
2.94348669 decagrams per quart = 1 troy ounces per liter.
troy ounces per liter = decagrams per quart × 0.339733148235
For a page dedicated to this direction, see Decagram per Quart to Troy ounce per Liter.
Understanding the Troy ounce per Liter (oz t/L)
Mass per volume density.
Understanding the Decagram per Quart (dag/qt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many decagrams per quart are in 1 troy ounce per liter?
1 troy ounce per liter equals 2.94348669 decagrams per quart, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per liter to decagram per quart?
Multiply the troy ounce per liter value by 2.94348669. The converter above does this instantly to whatever precision you set.
How do I convert decagram per quart back to troy ounce per liter?
Use the reverse factor: 1 decagram per quart equals 0.3397331482 troy ounces per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per liter?
Troy ounce per Liter (oz t/L) is a unit of density.
What is a decagram per quart?
Decagram per Quart (dag/qt) is a unit of density.
Is the troy ounce per liter to decagram per quart conversion exact?
Yes. Both troy ounce per liter and decagram per quart are defined by fixed standards rather than physical artifacts, so the factor of 2.94348669 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.