Mass per volume density.
Troy ounces per Liter to Hectograms per Pint Converter — oz t/L to hg/pt
Convert Troy ounce per Liter (oz t/L) to Hectogram per Pint (hg/pt) using the exact conversion factor (1 troy ounce per liter = 0.1471743345 hectogram per pint). See the formula, worked examples, and conversion table.
Troy ounces per Liter to Hectograms per Pint converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 31.1034768 / 211.3376419.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Liter to Hectograms per Pint
Troy ounce per Liter and Hectogram per Pint both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
hectograms per pint = troy ounces per liter × 0.147174334503
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per liter equals 31.1034768 base units, and 1 hectogram per pint equals 211.337641887 base units, so dividing one by the other gives the direct troy ounce per liter-to-hectogram per pint factor of 0.147174334503.
Simple example
1 oz t/L × 0.1471743345 = 0.1471743345 hg/pt
1 troy ounce per liter = 0.1471743345 hectograms per pint.
Real-world example
1,000 oz t/L × 0.1471743345 = 147.1743345 hg/pt
1,000 troy ounces per liter = 147.1743345 hectograms per pint.
Conversion table
| Troy ounce per Liter (oz t/L) | Hectogram per Pint (hg/pt) |
|---|---|
| 0.1 oz t/L | 0.0147174335 hg/pt |
| 1 oz t/L | 0.1471743345 hg/pt |
| 10 oz t/L | 1.471743345 hg/pt |
| 100 oz t/L | 14.71743345 hg/pt |
| 1,000 oz t/L | 147.1743345 hg/pt |
| 10,000 oz t/L | 1,471.743345 hg/pt |
Reverse conversion: Hectogram per Pint to Troy ounce per Liter
0.1471743345 hg/pt × 6.794662965 = 1 oz t/L
0.1471743345 hectograms per pint = 1 troy ounces per liter.
troy ounces per liter = hectograms per pint × 6.7946629647
For a page dedicated to this direction, see Hectogram per Pint to Troy ounce per Liter.
Understanding the Troy ounce per Liter (oz t/L)
Mass per volume density.
Understanding the Hectogram per Pint (hg/pt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many hectograms per pint are in 1 troy ounce per liter?
1 troy ounce per liter equals 0.1471743345 hectograms per pint, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per liter to hectogram per pint?
Multiply the troy ounce per liter value by 0.1471743345. The converter above does this instantly to whatever precision you set.
How do I convert hectogram per pint back to troy ounce per liter?
Use the reverse factor: 1 hectogram per pint equals 6.794662965 troy ounces per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per liter?
Troy ounce per Liter (oz t/L) is a unit of density.
What is a hectogram per pint?
Hectogram per Pint (hg/pt) is a unit of density.
Is the troy ounce per liter to hectogram per pint conversion exact?
Yes. Both troy ounce per liter and hectogram per pint are defined by fixed standards rather than physical artifacts, so the factor of 0.1471743345 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.