Mass per volume density.
Troy ounces per Liter to Kilograms per Quart Converter — oz t/L to kg/qt
Convert Troy ounce per Liter (oz t/L) to Kilogram per Quart (kg/qt) using the exact conversion factor (1 troy ounce per liter = 0.0294348669 kilogram per quart). See the formula, worked examples, and conversion table.
Troy ounces per Liter to Kilograms per Quart converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 31.1034768 / 1056.688209.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Liter to Kilograms per Quart
Troy ounce per Liter and Kilogram per Quart both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
kilograms per quart = troy ounces per liter × 0.0294348669005
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per liter equals 31.1034768 base units, and 1 kilogram per quart equals 1056.68820943 base units, so dividing one by the other gives the direct troy ounce per liter-to-kilogram per quart factor of 0.0294348669005.
Simple example
1 oz t/L × 0.0294348669 = 0.0294348669 kg/qt
1 troy ounce per liter = 0.0294348669 kilograms per quart.
Real-world example
1,000 oz t/L × 0.0294348669 = 29.4348669 kg/qt
1,000 troy ounces per liter = 29.4348669 kilograms per quart.
Conversion table
| Troy ounce per Liter (oz t/L) | Kilogram per Quart (kg/qt) |
|---|---|
| 0.1 oz t/L | 0.0029434867 kg/qt |
| 1 oz t/L | 0.0294348669 kg/qt |
| 10 oz t/L | 0.294348669 kg/qt |
| 100 oz t/L | 2.94348669 kg/qt |
| 1,000 oz t/L | 29.4348669 kg/qt |
| 10,000 oz t/L | 294.348669 kg/qt |
Reverse conversion: Kilogram per Quart to Troy ounce per Liter
0.0294348669 kg/qt × 33.97331482 = 1 oz t/L
0.0294348669 kilograms per quart = 1 troy ounces per liter.
troy ounces per liter = kilograms per quart × 33.9733148235
For a page dedicated to this direction, see Kilogram per Quart to Troy ounce per Liter.
Understanding the Troy ounce per Liter (oz t/L)
Mass per volume density.
Understanding the Kilogram per Quart (kg/qt)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many kilograms per quart are in 1 troy ounce per liter?
1 troy ounce per liter equals 0.0294348669 kilograms per quart, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per liter to kilogram per quart?
Multiply the troy ounce per liter value by 0.0294348669. The converter above does this instantly to whatever precision you set.
How do I convert kilogram per quart back to troy ounce per liter?
Use the reverse factor: 1 kilogram per quart equals 33.97331482 troy ounces per liter. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per liter?
Troy ounce per Liter (oz t/L) is a unit of density.
What is a kilogram per quart?
Kilogram per Quart (kg/qt) is a unit of density.
Is the troy ounce per liter to kilogram per quart conversion exact?
Yes. Both troy ounce per liter and kilogram per quart are defined by fixed standards rather than physical artifacts, so the factor of 0.0294348669 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.