Mass per volume density.
Troy ounces per Pint to Centigrams per Liter Converter — oz t/pt to cg/L
Convert Troy ounce per Pint (oz t/pt) to Centigram per Liter (cg/L) using the exact conversion factor (1 troy ounce per pint = 6,573.335441 centigram per liter). See the formula, worked examples, and conversion table.
Troy ounces per Pint to Centigrams per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 65.73335441 / 0.01.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Pint to Centigrams per Liter
Troy ounce per Pint and Centigram per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
centigrams per liter = troy ounces per pint × 6573.33544138
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per pint equals 65.7333544138 base units, and 1 centigram per liter equals 0.01 base units, so dividing one by the other gives the direct troy ounce per pint-to-centigram per liter factor of 6573.33544138.
Simple example
1 oz t/pt × 6573.335441 = 6,573.335441 cg/L
1 troy ounce per pint = 6,573.335441 centigrams per liter.
Real-world example
1,000 oz t/pt × 6573.335441 = 6,573,335.441 cg/L
1,000 troy ounces per pint = 6,573,335.441 centigrams per liter.
Conversion table
| Troy ounce per Pint (oz t/pt) | Centigram per Liter (cg/L) |
|---|---|
| 0.1 oz t/pt | 657.3335441 cg/L |
| 1 oz t/pt | 6,573.335441 cg/L |
| 10 oz t/pt | 65,733.35441 cg/L |
| 100 oz t/pt | 657,333.5441 cg/L |
| 1,000 oz t/pt | 6,573,335.441 cg/L |
| 10,000 oz t/pt | 65,733,354.41 cg/L |
Reverse conversion: Centigram per Liter to Troy ounce per Pint
1 cg/L × 0.0001521297687 = 0.0001521298 oz t/pt
1 centigram per liter = 0.0001521298 troy ounces per pint.
troy ounces per pint = centigrams per liter × 0.000152129768657
For a page dedicated to this direction, see Centigram per Liter to Troy ounce per Pint.
Understanding the Troy ounce per Pint (oz t/pt)
Mass per volume density.
Understanding the Centigram per Liter (cg/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many centigrams per liter are in 1 troy ounce per pint?
1 troy ounce per pint equals 6,573.335441 centigrams per liter, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per pint to centigram per liter?
Multiply the troy ounce per pint value by 6573.335441. The converter above does this instantly to whatever precision you set.
How do I convert centigram per liter back to troy ounce per pint?
Use the reverse factor: 1 centigram per liter equals 0.0001521298 troy ounces per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per pint?
Troy ounce per Pint (oz t/pt) is a unit of density.
What is a centigram per liter?
Centigram per Liter (cg/L) is a unit of density.
Is the troy ounce per pint to centigram per liter conversion exact?
Yes. Both troy ounce per pint and centigram per liter are defined by fixed standards rather than physical artifacts, so the factor of 6573.335441 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.