Mass per volume density.
Troy ounces per Pint to Long tons per Cup Converter — oz t/pt to long ton/cup
Convert Troy ounce per Pint (oz t/pt) to Long ton per Cup (long ton/cup) using the exact conversion factor (1 troy ounce per pint = 0.0000153061 long ton per cup). See the formula, worked examples, and conversion table.
Troy ounces per Pint to Long tons per Cup converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Mass per volume density.
Result = input x 65.73335441 / 4.29457916e+6.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Pint to Long tons per Cup
Troy ounce per Pint and Long ton per Cup both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
long tons per cup = troy ounces per pint × 0.000015306122449
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per pint equals 65.7333544138 base units, and 1 long ton per cup equals 4294579.15504 base units, so dividing one by the other gives the direct troy ounce per pint-to-long ton per cup factor of 0.000015306122449.
Simple example
1 oz t/pt × 0.00001530612245 = 0.0000153061 long ton/cup
1 troy ounce per pint = 0.0000153061 long tons per cup.
Real-world example
1,000 oz t/pt × 0.00001530612245 = 0.0153061225 long ton/cup
1,000 troy ounces per pint = 0.0153061225 long tons per cup.
Conversion table
| Troy ounce per Pint (oz t/pt) | Long ton per Cup (long ton/cup) |
|---|---|
| 0.1 oz t/pt | 0.0000015306 long ton/cup |
| 1 oz t/pt | 0.0000153061 long ton/cup |
| 10 oz t/pt | 0.0001530612 long ton/cup |
| 100 oz t/pt | 0.0015306122 long ton/cup |
| 1,000 oz t/pt | 0.0153061225 long ton/cup |
| 10,000 oz t/pt | 0.1530612245 long ton/cup |
Reverse conversion: Long ton per Cup to Troy ounce per Pint
0.0000153061 long ton/cup × 65333.33333 = 0.9999985333 oz t/pt
0.0000153061 long tons per cup = 0.9999985333 troy ounces per pint.
troy ounces per pint = long tons per cup × 65333.3333333
For a page dedicated to this direction, see Long ton per Cup to Troy ounce per Pint.
Understanding the Troy ounce per Pint (oz t/pt)
Mass per volume density.
Understanding the Long ton per Cup (long ton/cup)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many long tons per cup are in 1 troy ounce per pint?
1 troy ounce per pint equals 0.0000153061 long tons per cup, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per pint to long ton per cup?
Multiply the troy ounce per pint value by 0.00001530612245. The converter above does this instantly to whatever precision you set.
How do I convert long ton per cup back to troy ounce per pint?
Use the reverse factor: 1 long ton per cup equals 65,333.33333 troy ounces per pint. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per pint?
Troy ounce per Pint (oz t/pt) is a unit of density.
What is a long ton per cup?
Long ton per Cup (long ton/cup) is a unit of density.
Is the troy ounce per pint to long ton per cup conversion exact?
Yes. Both troy ounce per pint and long ton per cup are defined by fixed standards rather than physical artifacts, so the factor of 0.00001530612245 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.