Mass per volume density.
Troy ounces per Quart to Decagrams per Liter Converter — oz t/qt to dag/L
Convert Troy ounce per Quart (oz t/qt) to Decagram per Liter (dag/L) using the exact conversion factor (1 troy ounce per quart = 3.286667721 decagram per liter). See the formula, worked examples, and conversion table.
Troy ounces per Quart to Decagrams per Liter converter
Converter
Density Converter
Convert thousands of mass-per-volume density combinations for science, engineering, agriculture, and fluids.
Context values
Some unit families need one extra value for a physically accurate result.
Mass per volume density.
Result = input x 32.86667721 / 10.
Density uses kilograms per cubic meter as the base unit.
Reserved above the conversion cards and below the converter.
About Converting Troy ounces per Quart to Decagrams per Liter
Troy ounce per Quart and Decagram per Liter both measure density — mass per unit volume — a property used to identify materials, check manufacturing quality, and predict whether something floats or sinks. As a fixed reference point, water has a density of exactly 1000 kg/m³ (1 g/cm³, 1 g/mL) at its temperature of maximum density, which is why many density figures in science and engineering are quoted relative to water. Both are mass per volume density units.
Formula
decagrams per liter = troy ounces per quart × 3.28666772069
This factor comes from each unit's defined relationship to the category's base unit: 1 troy ounce per quart equals 32.8666772069 base units, and 1 decagram per liter equals 10 base units, so dividing one by the other gives the direct troy ounce per quart-to-decagram per liter factor of 3.28666772069.
Simple example
1 oz t/qt × 3.286667721 = 3.286667721 dag/L
1 troy ounce per quart = 3.286667721 decagrams per liter.
Real-world example
1,000 oz t/qt × 3.286667721 = 3,286.667721 dag/L
1,000 troy ounces per quart = 3,286.667721 decagrams per liter.
Conversion table
| Troy ounce per Quart (oz t/qt) | Decagram per Liter (dag/L) |
|---|---|
| 0.1 oz t/qt | 0.3286667721 dag/L |
| 1 oz t/qt | 3.286667721 dag/L |
| 10 oz t/qt | 32.86667721 dag/L |
| 100 oz t/qt | 328.6667721 dag/L |
| 1,000 oz t/qt | 3,286.667721 dag/L |
| 10,000 oz t/qt | 32,866.67721 dag/L |
Reverse conversion: Decagram per Liter to Troy ounce per Quart
3.286667721 dag/L × 0.3042595373 = 1 oz t/qt
3.286667721 decagrams per liter = 1 troy ounces per quart.
troy ounces per quart = decagrams per liter × 0.304259537313
For a page dedicated to this direction, see Decagram per Liter to Troy ounce per Quart.
Understanding the Troy ounce per Quart (oz t/qt)
Mass per volume density.
Understanding the Decagram per Liter (dag/L)
Mass per volume density.
Reserved between the cards and the FAQ so the page stays balanced.
Frequently asked questions
How many decagrams per liter are in 1 troy ounce per quart?
1 troy ounce per quart equals 3.286667721 decagrams per liter, using the exact defined conversion factor rather than an estimate.
How do I convert troy ounce per quart to decagram per liter?
Multiply the troy ounce per quart value by 3.286667721. The converter above does this instantly to whatever precision you set.
How do I convert decagram per liter back to troy ounce per quart?
Use the reverse factor: 1 decagram per liter equals 0.3042595373 troy ounces per quart. You can also use the swap control in the converter above to flip the direction instantly.
What is a troy ounce per quart?
Troy ounce per Quart (oz t/qt) is a unit of density.
What is a decagram per liter?
Decagram per Liter (dag/L) is a unit of density.
Is the troy ounce per quart to decagram per liter conversion exact?
Yes. Both troy ounce per quart and decagram per liter are defined by fixed standards rather than physical artifacts, so the factor of 3.286667721 used above is exact to as many digits as you choose to display.
What's the difference between density and mass concentration?
Density is the mass of a pure substance or material per unit volume. Mass concentration is the mass of one component — like a dissolved solute — within a mixture's total volume. The two use the same kind of units but describe different physical situations.